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Correct statement regarding molecules SF...

Correct statement regarding molecules `SF_(4),CF_(4) and XeF_(4)` are :

A

2,0 and 1 lone pairs of central atom respectively

B

1,0 and 1 lone pairs of central atom respectively

C

0,0 and 2 lone pairs of central atom respectively

D

1,0 and 2 lone pairs of central atom respectively

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The correct Answer is:
To analyze the molecules SF₄, CF₄, and XeF₄ regarding their lone pairs on the central atom, we can follow these steps: ### Step-by-Step Solution: 1. **Identify the central atom and its valence electrons**: - **SF₄ (Sulfur Tetrafluoride)**: - Sulfur (S) is the central atom. It is in group 16 and has 6 valence electrons. - **CF₄ (Carbon Tetrafluoride)**: - Carbon (C) is the central atom. It is in group 14 and has 4 valence electrons. - **XeF₄ (Xenon Tetrafluoride)**: - Xenon (Xe) is the central atom. It is a noble gas in group 18 and has 8 valence electrons. 2. **Determine the number of bond pairs formed**: - In each molecule, the central atom forms bonds with four fluorine atoms. - Each bond with a fluorine atom uses one valence electron from the central atom. 3. **Calculate the number of lone pairs**: - **For SF₄**: - Sulfur has 6 valence electrons. - It forms 4 bond pairs with fluorine (4 electrons used). - Remaining electrons = 6 - 4 = 2 electrons. - These 2 electrons form 1 lone pair (since 2 electrons make 1 lone pair). - **For CF₄**: - Carbon has 4 valence electrons. - It forms 4 bond pairs with fluorine (4 electrons used). - Remaining electrons = 4 - 4 = 0 electrons. - Therefore, there are 0 lone pairs. - **For XeF₄**: - Xenon has 8 valence electrons. - It forms 4 bond pairs with fluorine (4 electrons used). - Remaining electrons = 8 - 4 = 4 electrons. - These 4 electrons form 2 lone pairs (since 4 electrons make 2 lone pairs). 4. **Summarize the findings**: - **SF₄**: 1 lone pair - **CF₄**: 0 lone pairs - **XeF₄**: 2 lone pairs 5. **Conclusion**: - The correct statement regarding the lone pairs in these molecules is: - SF₄ has 1 lone pair, CF₄ has 0 lone pairs, and XeF₄ has 2 lone pairs. ### Final Answer: - SF₄ has 1 lone pair, CF₄ has 0 lone pairs, and XeF₄ has 2 lone pairs.
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VK JAISWAL ENGLISH-CHEMICAL BONDING (BASIC)-SUBJECTIVE PROBLEMS
  1. Correct statement regarding molecules SF(4),CF(4) and XeF(4) are :

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  2. Consider following compounds A to E : (A) XeF(n) " " (B) XeF((n+1)...

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  3. Consider the following five group (According to modern periodic table)...

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  4. Consider the following species and find out total number of species wh...

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  5. Consider the following table regarding interhalogen compounds, XY(n) (...

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  6. What is covalency of chlorine atom in second excited state ?

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  7. Sum of sigma and pi bonds in NH(4)^(+) cation is ..

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  8. Calculate the value of X-Y, for XeOF(4). (X=Number of sigma bond pair ...

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  9. The molecule ABn is planar with six pairs of electrons around A in the...

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  10. Calculate value of (X+Y+Z)/(10), here X is O-N-O bond angle in NO(3)^(...

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  11. Calculate x+y+z for H(3)PO(3) acid, where x is no. of lone pairs, y is...

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  12. How many right angle, bond angles are present in TeF(5)^(-) molecular ...

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  13. How may possible angle FSeF bond angles are present in SeF(4) molecule...

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  14. In IF(6)^(-) and TeF(5)^(-), sum of axial d-orbitals which are used in...

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  15. Among the following, total no. of planar species is : (i) SF(4) " "...

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  16. Calculate the value of " x+y-z" here x,y and z are total number of non...

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  17. Consider the following table Then calculate value of "p+q+r-s-t".

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  18. In phosphorus acid, if X is number of non bonding electron pairs. Y is...

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  19. Calculate the number of p(pi)-d(pi) bond(s) present in SO(4)^(2-) :

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  20. Sum of sigma and pi bonds in NH(4)^(+) cation is ..

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  21. Consider the following orbitals (i)3p(x) (ii)4d(z^(2)) (iii)3d(x^(2)...

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