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Assuming pure 2s and 2p orbitals of carb...

Assuming pure 2s and 2p orbitals of carbon are used in forming `CH_(4)` molecule, which of the following statement is false ?

A

Three C-H bonds will be at right angle

B

One C-H bond will be weaker than other three C-H bonds

C

The shape of molecule will be tetrahedral

D

The angle of C-H bond formed by s-s overlapping will be uncertain with respect to other three bonds.

Text Solution

AI Generated Solution

The correct Answer is:
To determine which statement is false regarding the formation of the `CH₄` molecule (methane) using pure 2s and 2p orbitals of carbon, we will analyze each option step by step. ### Step-by-Step Solution: 1. **Understanding the Hybridization**: - In a typical scenario, carbon undergoes sp³ hybridization to form methane, resulting in four equivalent bonds with a tetrahedral geometry. However, the question specifies that we assume pure 2s and 2p orbitals are used, which means no hybridization occurs. 2. **Analyzing the Bond Angles**: - In the case of pure 2p orbitals, the three 2p orbitals (px, py, pz) are oriented at right angles (90 degrees) to each other. Therefore, if we consider the bonds formed by these orbitals overlapping with hydrogen's 1s orbital, the three bonds formed by the 2p orbitals will indeed be at right angles to each other. 3. **Evaluating Each Statement**: - **Option A**: "3 CH bonds will be at right angle." - This statement is **true** because the 2p orbitals are oriented at 90 degrees to each other. - **Option B**: "1 CH bond will be weaker than other 3 CH bonds." - This statement is also **true**. The bond formed by the overlap of the 2s orbital and 1s orbital (2s-1s bond) is stronger than the bonds formed by the 2p orbitals (2p-1s bonds) due to the nature of the overlapping orbitals. - **Option C**: "The shape of the molecule will be tetrahedral." - This statement is **false**. Since we are assuming pure 2s and 2p orbitals without hybridization, the geometry cannot be tetrahedral. The angles cannot be 109.5 degrees, and the bond strengths will differ, thus not forming a stable tetrahedral structure. - **Option D**: "The angle of CH bond formed by SS overlapping will be uncertain with respect to other three bonds." - This statement is **true**. The angle of the bond formed by the 2s-1s overlap is not defined in relation to the 2p-1s bonds, making it uncertain. 4. **Conclusion**: - The false statement among the options is **Option C**: "The shape of the molecule will be tetrahedral."

To determine which statement is false regarding the formation of the `CH₄` molecule (methane) using pure 2s and 2p orbitals of carbon, we will analyze each option step by step. ### Step-by-Step Solution: 1. **Understanding the Hybridization**: - In a typical scenario, carbon undergoes sp³ hybridization to form methane, resulting in four equivalent bonds with a tetrahedral geometry. However, the question specifies that we assume pure 2s and 2p orbitals are used, which means no hybridization occurs. 2. **Analyzing the Bond Angles**: ...
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