Out of `CHCl_(3), CH_(4) and SF_(4)` the molecules do not having regular geometry are:

Options

A. `CHCl_(3)` only
B. `CHCl_(3) and SF_(4)`
C. `CH_(4)`
D. `CH_(4) and SF_(4)`

Answer

To determine which of the molecules CHCl₃, CH₄, and SF₄ do not have regular geometry, we need to analyze the molecular structures and the presence of lone pairs on the central atoms.

### Step-by-Step Solution:

1. **Identify the Central Atom and Valency**:
- For **CHCl₃**: The central atom is Carbon (C), which has a valency of 4. It is bonded to three Chlorine (Cl) atoms and one Hydrogen (H) atom.
- For **CH₄**: The central atom is Carbon (C), which has a valency of 4. It is bonded to four Hydrogen (H) atoms.
- For **SF₄**: The central atom is Sulfur (S), which has a valency of 6. It is bonded to four Fluorine (F) atoms.

2. **Determine the Geometry**:
- **CHCl₃**: The carbon atom is bonded to three Cl atoms and one H atom, which means it is not bonded to the same type of atom (Cl and H are different). Additionally, carbon has no lone pairs. The geometry is **trigonal pyramidal**, which is not regular due to the presence of different atoms.
- **CH₄**: The carbon atom is bonded to four identical Hydrogen atoms. There are no lone pairs on the carbon atom. The geometry is **tetrahedral**, which is regular.
- **SF₄**: The sulfur atom is bonded to four Fluorine atoms, but it also has one lone pair. The presence of the lone pair distorts the geometry, resulting in a **seesaw** shape, which is not regular.

3. **Conclusion**:
- **CHCl₃** does not have regular geometry because it is bonded to different atoms.
- **CH₄** has regular geometry because it is bonded to the same atoms and has no lone pairs.
- **SF₄** does not have regular geometry due to the presence of a lone pair.

### Final Answer:
The molecules that do not have regular geometry are **CHCl₃** and **SF₄**.