The IUPAC name of `Xe[PtF_(6)]` is:

Options

A. Hexafluoroplatinate(VI) xenon
B. Xenonhexafluoroplatinate(IV)
C. Xenonhexafluoroplatinate(VI)
D. Xenoniumhexafluoroplatinum(V)

Answer

To determine the IUPAC name of the coordination compound `Xe[PtF_(6)]`, we can follow these steps:

### Step 1: Identify the components of the compound
The compound consists of xenon (Xe) and a platinum complex with six fluoride ligands. The platinum complex can be represented as `[PtF6]`.

### Step 2: Determine the oxidation state of platinum
To find the oxidation state of platinum (Pt) in the complex, we can use the following formula:

\[ \text{Oxidation state of Pt} + 6 \times (\text{oxidation state of F}) = \text{charge of the complex} \]

Fluorine (F) has an oxidation state of -1. Therefore, we can set up the equation:

\[ x + 6 \times (-1) = 0 \]

Solving for \(x\):

\[ x - 6 = 0 \implies x = +6 \]

So, the oxidation state of platinum (Pt) in this complex is +6.

### Step 3: Identify the ligands and their names
The ligands in this complex are fluoride ions (F^-). According to IUPAC nomenclature, when naming ligands, we use the prefix "fluoro" for fluoride ions. Since there are six fluoride ions, we use the prefix "hexa-".

### Step 4: Combine the names
The name of the complex will start with the name of the ligands followed by the name of the metal. Since the oxidation state of platinum is +6, we will use "platin" and add the suffix "-ate" to indicate that it is a complex anion.

### Step 5: Write the full name
Putting it all together, we have:

- Ligand: Hexafluoro
- Metal: Platinum (with the oxidation state indicated as -ate)

Thus, the full IUPAC name of the compound `Xe[PtF_(6)]` is:

**Xenon hexafluoroplatinate(VI)**

### Final Answer:
**Xenon hexafluoroplatinate(VI)**

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