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Number of circle touching both the axes ...

Number of circle touching both the axes and the line `x+y=4` is greater than or equal to : (a) 1 (b) 2 (c) 3 (d) 4

A

1

B

2

C

3

D

4

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem of finding the number of circles that touch both the axes and the line \(x + y = 4\), we can follow these steps: ### Step 1: Understand the Geometry We need to visualize the situation. The line \(x + y = 4\) intersects the x-axis at the point (4, 0) and the y-axis at the point (0, 4). This line divides the first quadrant into two regions. **Hint:** Sketch the coordinate axes and the line \(x + y = 4\) to better understand the area in which the circles can be drawn. ### Step 2: Determine the Circle's Properties A circle that touches both axes will have its center at a point \((r, r)\), where \(r\) is the radius of the circle. The equation of such a circle can be written as: \[ (x - r)^2 + (y - r)^2 = r^2 \] **Hint:** Remember that the distance from the center of the circle to the axes must equal the radius \(r\). ### Step 3: Find the Condition for Touching the Line For the circle to touch the line \(x + y = 4\), the distance from the center \((r, r)\) to the line must equal the radius \(r\). The formula for the distance \(d\) from a point \((x_0, y_0)\) to a line \(Ax + By + C = 0\) is given by: \[ d = \frac{|Ax_0 + By_0 + C|}{\sqrt{A^2 + B^2}} \] For the line \(x + y - 4 = 0\), we have \(A = 1\), \(B = 1\), and \(C = -4\). **Hint:** Substitute the coordinates of the center \((r, r)\) into the distance formula. ### Step 4: Set Up the Equation Substituting \((r, r)\) into the distance formula: \[ d = \frac{|1 \cdot r + 1 \cdot r - 4|}{\sqrt{1^2 + 1^2}} = \frac{|2r - 4|}{\sqrt{2}} \] Setting this equal to the radius \(r\): \[ \frac{|2r - 4|}{\sqrt{2}} = r \] **Hint:** Simplify this equation to find the values of \(r\). ### Step 5: Solve the Equation Cross-multiplying gives: \[ |2r - 4| = r\sqrt{2} \] This leads to two cases: 1. \(2r - 4 = r\sqrt{2}\) 2. \(2r - 4 = -r\sqrt{2}\) **Hint:** Solve both cases separately to find the possible values of \(r\). ### Step 6: Analyze the Solutions After solving both cases, you will find that there are multiple values of \(r\) that satisfy the conditions. Each valid \(r\) corresponds to a circle that touches both axes and the line. **Hint:** Count the number of valid solutions for \(r\) to determine how many circles can be drawn. ### Conclusion Based on the analysis, we find that there are at least 4 circles that can satisfy the conditions given in the problem. Thus, the answer to the question is: **(d) 4**
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Knowledge Check

  • The equation of a circle which touches both the coordinate axes and the line x = 3 is

    A
    `4x^(2) + 4y^(2) - 12 x pm 12 y + 9 = 0 `
    B
    `4x^(2) + 4y^(2) + 12 x pm 12 y + 9 = 0 `
    C
    `4x^(2) + 4y ^(2) pm 12 x - 12 y + 9 = 0 `
    D
    ` 4x ^(2) + 4y^(2) pm 12x + 12 y + 9 = 0 `
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