Home
Class 11
BIOLOGY
If the GFR is 125 mL/min and the renal p...

If the GFR is 125 mL/min and the renal plasma flow is 700 mL/min, the filtration fraction is

A

About 6%

B

About 18%

C

About 12%

D

About 24%

Text Solution

AI Generated Solution

The correct Answer is:
To find the filtration fraction (FF), we can follow these steps: ### Step-by-Step Solution: 1. **Understand the Definitions**: - **GFR (Glomerular Filtration Rate)**: The amount of filtrate formed by the kidneys per minute. In this case, GFR = 125 mL/min. - **RPF (Renal Plasma Flow)**: The amount of blood plasma delivered to the kidneys per minute. In this case, RPF = 700 mL/min. 2. **Formula for Filtration Fraction**: - The filtration fraction (FF) can be calculated using the formula: \[ \text{FF} = \frac{\text{GFR}}{\text{RPF}} \] 3. **Substitute the Values**: - Substitute the given values into the formula: \[ \text{FF} = \frac{125 \, \text{mL/min}}{700 \, \text{mL/min}} \] 4. **Calculate the Filtration Fraction**: - Perform the division: \[ \text{FF} = \frac{125}{700} \approx 0.17857 \] 5. **Convert to Percentage**: - To express the filtration fraction as a percentage, multiply by 100: \[ \text{FF} \approx 0.17857 \times 100 \approx 17.857 \% \] 6. **Round the Answer**: - Rounding to one decimal place gives us: \[ \text{FF} \approx 18\% \] ### Final Answer: The filtration fraction is approximately **18%**. ---
Doubtnut Promotions Banner Mobile Dark
|

Topper's Solved these Questions

  • EXCERETORY PRODUCTS AND THEIR ELIMINATION

    CENGAGE BIOLOGY ENGLISH|Exercise ASSERTION-REASONING QUESTIONS|10 Videos
  • EXCERETORY PRODUCTS AND THEIR ELIMINATION

    CENGAGE BIOLOGY ENGLISH|Exercise ARCHIVES|22 Videos
  • DIGESTION AND ABSORPTION

    CENGAGE BIOLOGY ENGLISH|Exercise ARCHIVES|25 Videos
  • LOCOMOTION AND MOVEMENT

    CENGAGE BIOLOGY ENGLISH|Exercise ARCHIVES|12 Videos

Similar Questions

Explore conceptually related problems

what is the renal plasma flow if GFR is 125 ml/min . and filtration fraction is 20% ?

Almost 1300ml of blood pressure through the kidney per minute.Out of this, 125 ml, fibrate is formed by glomeruli per minute.So the normal filtration fraction is

Find the fractions: 5 mL of a litre

What fraction is? 250 mL of 2L

What fraction is 300 mL of 1 L?

If the stroke volume of an athlete is 100 ml and the heart beat rate is 82/min, what will be the cardiac output ?

What fraction of a reactant remains unreacted after 40 min if t_(1//2) is of the reaction is 20 min? consider the reaction is first order

Aqueous AB_(2) decomposes according to the first order reaction: AB_(2)(aq) rarr A(g) + 2B(l) After 20 min the volume of A(g) colledcted during such a reaction is 20 mL , and that collected after a very long time is 40 mL . The rate constant is :

100 mL sample of hard water is titrated with 500 " mL of " 0.001 M EDTA solution at pH=10 , using eriochrome black-T indicator to reach equivalence point. An equal another amount of hard water sample is boiled for 30 min. After filtration and cooling, the same sample is titrated with 200 " mL of " 0.011 M EDTA solution at pH=10 using Mg-EDTA complex solution and erichrome black-T indicator to reach equivalence point. (i). Calculate the total hardness of water sample (temporary + permanent) in ppm of CaCO_3 .

A liquid of coefficient of viscosity eta=1 poise is flowing in a pipe of radius 3 cm such that the rate of volume flow is 1000 l//min .Determine the Reynolds numbers. (A) 3536 (B) 3500 (C) 3400 (D) 3600