A lamina is made by removing a small disc of diameter 2R from a bigger disc of uniform mass density and radius 2R, as shown in the figure. The moment of inertia of this lamina about axes passing though O and P is `I_O and I_P` respectively. Both these axes are perpendicular to the plane of the lamina. The ratio `I_P/I_O` is
A disc has mass 9 m. A hole of radius R/3 is cut from it as shown in the figure. The moment of inertia of remaining part about an axis passing through the centre 'O' of the disc and perpendicular to the plane of the disc is :
A lamina is made by removing a small disc of diameter 2 R from a bigger disc of uniform mass density and radius 2R, as shown in figure. A second similar disc is made but instead of hole a disc of triple the density as of first it filled in the hole. Centre of mass is calculated in both the cases and was found at a distance r_(1) & r_(2) from centre O respectively find the ratio |(2r_(2))/(r_(1))|
A square lamina is as shown in figure. The moment of inertia of the frame about the three axes as shown in figure I_(1),I_(2) and I_(3) respectively. Select the correct alternative.
In the figure shown ABCD is a lamina of mass 12 kg . The moment of inertia of the given body about an axis passing through D, and perpendicular to the plane of the body is
A system of uniform rod of mass m and length 2R and a uniform disc of m and radius R are as shown in the figure. The moment of inertia of the system about the axis OO^' (perpendicular to plane of disc) will be
A uniform semi-circular disc of mass m and radius r is suspended as shown in the figure. If T is the time period of small osciallations about an axis passing through point of supension and perpendicular to plane of disk. Then T is equal to
The masses of two uniform discs are in the ratio 1 : 2 and their diameters in the ratio 2 : 1 . The ratio of their moment, of inertia about the axis passing through their respective centres and perpendicular to their planes is
From a disc of mass 2kg and radius 4m a small disc of radius 1 m with center O' is extracted . The new moment of inertia,about an axis passing through O perpendicular to plane of disc is
Moment of inertia of a uniform quarter disc of radius R and mass M about an axis through its centre of mass and perpendicular to its plane is :
Moment of inertia of a uniform quarter disc of radius R and mass M about an axis through its centre of mass and perpendicular to its plane is :
CENGAGE PHYSICS ENGLISH-RIGID BODY DYNAMICS 2-Interger
`I_0=((4m)(2R)^(2))/2-3/2mR^(2)=mR^(2)[8-3/2]=13/2mR^(2)` 
