A pipe of non uniform cross section has two distinct section ` 1` and `2 ` with areas `2cm^(2)` and `4cm^(2)` respectively. If the velocity of flowing liquid at section `1` is `5cm//s`, determine the velocity at section `2`.

Explanation

To solve the problem of determining the velocity at section 2 of a pipe with non-uniform cross-section, we can use the principle of conservation of mass, which is represented by the continuity equation. Here’s a step-by-step solution:

### Step 1: Identify the given values
- Cross-sectional area at section 1, \( A_1 = 2 \, \text{cm}^2 \)
- Cross-sectional area at section 2, \( A_2 = 4 \, \text{cm}^2 \)
- Velocity at section 1, \( V_1 = 5 \, \text{cm/s} \)

### Step 2: Write the continuity equation
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