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An iceberg is floating partially immerse...

An iceberg is floating partially immersed in sea water. The density of sea water is `1.03 g cm^(-3)` and that of ice is`0.92 g cm^(-3)`. The approximate percentage of total volume of iceberg above the level of sea water is

A

`8`

B

`11`

C

`34`

D

`89`

Text Solution

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The correct Answer is:
To solve the problem of determining the approximate percentage of the total volume of an iceberg that is above the level of seawater, we can follow these steps: ### Step 1: Understand the relationship between the densities and volumes When an object floats, the weight of the object is equal to the weight of the fluid it displaces. This can be expressed as: \[ \text{Weight of Iceberg} = \text{Weight of Displaced Water} \] ### Step 2: Define the variables Let: - \( V \) = total volume of the iceberg - \( x \) = volume of the iceberg submerged in water - \( \rho_{\text{ice}} \) = density of ice = \( 0.92 \, \text{g/cm}^3 \) - \( \rho_{\text{water}} \) = density of seawater = \( 1.03 \, \text{g/cm}^3 \) ### Step 3: Write the equation for buoyancy The weight of the iceberg can be expressed as: \[ \text{Weight} = \rho_{\text{ice}} \cdot V \cdot g \] The weight of the displaced water can be expressed as: \[ \text{Weight} = \rho_{\text{water}} \cdot x \cdot g \] Setting these equal gives: \[ \rho_{\text{ice}} \cdot V = \rho_{\text{water}} \cdot x \] ### Step 4: Relate submerged volume to total volume From the equation above, we can rearrange to find the ratio of submerged volume to total volume: \[ \frac{x}{V} = \frac{\rho_{\text{ice}}}{\rho_{\text{water}}} \] ### Step 5: Substitute the known densities Substituting the values for the densities: \[ \frac{x}{V} = \frac{0.92}{1.03} \] ### Step 6: Calculate the submerged volume ratio Calculating the above gives: \[ \frac{x}{V} \approx 0.8922 \] This means approximately 89.22% of the iceberg's volume is submerged in water. ### Step 7: Calculate the volume above the water level The volume of the iceberg above the water level is: \[ V_{\text{above}} = V - x = V - 0.8922V = (1 - 0.8922)V = 0.1078V \] ### Step 8: Calculate the percentage of volume above the water level To find the percentage of the total volume that is above the water level: \[ \text{Percentage above} = \left(\frac{V_{\text{above}}}{V}\right) \times 100 = 0.1078 \times 100 \approx 10.78\% \] ### Step 9: Round to the nearest option Rounding 10.78% gives approximately 11%. ### Final Answer The approximate percentage of the total volume of the iceberg above the level of seawater is **11%**. ---

To solve the problem of determining the approximate percentage of the total volume of an iceberg that is above the level of seawater, we can follow these steps: ### Step 1: Understand the relationship between the densities and volumes When an object floats, the weight of the object is equal to the weight of the fluid it displaces. This can be expressed as: \[ \text{Weight of Iceberg} = \text{Weight of Displaced Water} \] ### Step 2: Define the variables Let: ...
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Knowledge Check

  • At 100°C and 1 atm, if the density of liquid water is 1.0 g cm^(-3) and that of water vapour is 0.0006 gcm-3 , then the volume occupied by water molecules in 1 litre of steam at that temperature is:

    A
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    B
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    C
    `0.6 cm^(3)`
    D
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