Home
Class 12
PHYSICS
Charges Q1 and Q2 are given to two plate...

Charges `Q_1` and `Q_2` are given to two plates fo a parllel plate capacitor. The capacity of the capacitor is `C`. When the switch is closed , mark correct statement (s) . (Assume both `Q_1` and `Q_2` to be positive).

A

The charge flowing through switch is zero.

B

The chrage flowing through the switch is `Q_(1)+Q_(2)`.

C

Potential difference across the capacitor plate is `Q_(1)//C`.

D

the charge of the capacitor is `Q_(1)`.

Text Solution

Verified by Experts

The correct Answer is:
B, C, D

As the switch is closed, the charge on the outer surface of the second plate becomes zero. Form the concept in electrostatics that electric field inside the bulk of the material of conductor is zero, we can dind the charges on various faces. So it is clear that `Q_(1)+Q_(2)` charge goes from the second plate to the earth. Charge on capacitor is `Q_(1)` and hence its potential is `Q_(1)//C`.
.
Doubtnut Promotions Banner Mobile Dark
|

Topper's Solved these Questions

  • CAPACITOR AND CAPACITANCE

    CENGAGE PHYSICS ENGLISH|Exercise Comprhension|35 Videos
  • CAPACITOR AND CAPACITANCE

    CENGAGE PHYSICS ENGLISH|Exercise Integer|5 Videos
  • CAPACITOR AND CAPACITANCE

    CENGAGE PHYSICS ENGLISH|Exercise Single Correct|49 Videos
  • ATOMIC PHYSICS

    CENGAGE PHYSICS ENGLISH|Exercise ddp.4.3|15 Videos
  • CENGAGE PHYSICS DPP

    CENGAGE PHYSICS ENGLISH|Exercise subjective type|51 Videos

Similar Questions

Explore conceptually related problems

Each plate of a parallel plate capacitor has a charge q on it. The capacitor is now connected to a battery. Now,

Consider a parallel plate capacitor having charge Q. Then,

Identify the correct statement about the charges q_1 and q_2 then

In the circuit shown, the capacitor C_1 is initially charged with charge q_0 . The switch S is closed at time t = 0 . The charge on C_2 after time t is

Suppose a charge +Q_1 is given to the positive plates and a charge -Q_2 to the negative plate of a capacitor. What is the "charge on the capacitor"?

A dielectric slab is inserted between the plates of a capacitor. The charge on the capacitor is Q and the magnitude of the induced charge on each surface of the dielectric is Q' .

In a parallel-plate capacitor of plate area A , plate separation d and charge Q the force of attraction between the plates is F .

In figure , the plates of a parallel plate capacitors have unequal charges. Its capacitance is C. P is a point outside the capacitor and close to the plate of charge -Q. The distance between the plates is d. Then

The electrostatic force between the metal plate of an isolated parallel plate capacitor C having charge Q and area A , is

The plates of small size of a parallel plate capacitor are charged as shown. The force on the charged particle of 'q' at a distance 'l' from the capacitor is : (Assume that the distance between the plates is d ltlt l )