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When an AC source of emf E=E(0)sin(100t)...

When an AC source of emf `E=E_(0)sin(100t)` is connected across a circuit, the phase difference between the emf E and the current I is observed be `pi/4`, as shown in the figure. If the circuit consists possibly only of R-C or R-L in series, which of the following combinations is possible?

A

`R=1 kOmega, C=10 (mu)F`

B

`R=1 kOmega, C=1(mu)F`

C

`R=1 kOmega,L=10H`

D

`R=1 kOmega, L=H`

Text Solution

Verified by Experts

The correct Answer is:
A
Since currents leads emf, therefore, this is an R-C circuit.
`tan phi=(X_(C )-X_(L))/(R ) here phi=45^(@)`
`:. X_(C )=R` [`X_(L)=0` as there is no inductor]
`(1)/(omega C)=R`
L.H.S `=(1)/(100 xx 10 xx 10^(-6)) = R = (10^3) Omega`.
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