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For an ideal gas...

For an ideal gas

A

The change in internal energy in a constant pressure process from temperature `T_1` to `T_2` is equal to `nCv(T_2-T_1)`, where Cv is the molar specific heat at constant volume and n the number of moles of the gas.

B

The change in internal energy of the gas and the work done by the gas are equal in magnitude in an adiabatic process.

C

The internal energy does not change in an isothermal process.

D

No heat is added or removed in an adiabatic process.

Text Solution

Verified by Experts

The correct Answer is:
A, B, C, D

`DeltaU=nC_(v)DeltaT rarr` for any process
In adiabatic process: `DeltaQ=0` , so `DeltaU=-Deltaw implies |DeltaU|=|Deltaw|`
In isothemal process, `DeltaT=0` , so `DeltaU=0`
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Knowledge Check

  • In an adiabatic expansion of an ideal gas -

    A
    (a) `W=-DeltaU`
    B
    (b) `W=DeltaU`
    C
    (c) `DeltaU=0`
    D
    (d) `W = 0 `
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