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What is the percentage change in the ten...

What is the percentage change in the tension necessary in a somometer of fixed length to produce a note one octave lower (half of original frequency) than before?

A

`25%`

B

`50%`

C

`67%`

D

`75%`

Text Solution

AI Generated Solution

The correct Answer is:
To find the percentage change in the tension necessary in a somometer of fixed length to produce a note one octave lower (which corresponds to half of the original frequency), we can follow these steps: ### Step-by-Step Solution: 1. **Understand the relationship between frequency and tension**: The frequency \( f \) of a vibrating string is given by the formula: \[ f = \frac{1}{2L} \sqrt{\frac{T}{\mu}} \] where: - \( L \) is the length of the string (fixed in this case), - \( T \) is the tension in the string, - \( \mu \) is the mass per unit length of the string. 2. **Establish the relationship between frequency and tension**: From the formula, we can see that frequency is directly proportional to the square root of the tension: \[ f \propto \sqrt{T} \] Therefore, if the frequency changes, the tension must change accordingly. 3. **Define the frequencies**: Let \( f_1 \) be the original frequency and \( f_2 \) be the new frequency (one octave lower). Since one octave lower means half the frequency: \[ f_2 = \frac{1}{2} f_1 \] 4. **Relate the tensions**: Using the relationship between frequency and tension: \[ \frac{f_1}{f_2} = \sqrt{\frac{T_1}{T_2}} \] Substituting \( f_2 \): \[ \frac{f_1}{\frac{1}{2} f_1} = \sqrt{\frac{T_1}{T_2}} \implies 2 = \sqrt{\frac{T_1}{T_2}} \] 5. **Square both sides**: Squaring both sides gives: \[ 4 = \frac{T_1}{T_2} \implies T_1 = 4T_2 \] 6. **Calculate the percentage change in tension**: The percentage change in tension is given by: \[ \text{Percentage Change} = \frac{T_1 - T_2}{T_1} \times 100 \] Substituting \( T_1 = 4T_2 \): \[ \text{Percentage Change} = \frac{4T_2 - T_2}{4T_2} \times 100 = \frac{3T_2}{4T_2} \times 100 = \frac{3}{4} \times 100 = 75\% \] ### Final Answer: The percentage change in tension necessary to produce a note one octave lower is **75%**.

To find the percentage change in the tension necessary in a somometer of fixed length to produce a note one octave lower (which corresponds to half of the original frequency), we can follow these steps: ### Step-by-Step Solution: 1. **Understand the relationship between frequency and tension**: The frequency \( f \) of a vibrating string is given by the formula: \[ f = \frac{1}{2L} \sqrt{\frac{T}{\mu}} ...
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