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Dimensional formula ML^(-1)T^2 does not ...

Dimensional formula `ML^(-1)T^2` does not represent the physical quantity

A

young's modulus of elasticity

B

stress

C

strain

D

pressure

Text Solution

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The correct Answer is:
To determine which physical quantity does not have the dimensional formula \( ML^{-1}T^{-2} \), we will analyze the dimensions of Young's modulus, stress, strain, and pressure. ### Step-by-Step Solution: 1. **Understanding the Given Dimensional Formula**: The dimensional formula we are examining is \( ML^{-1}T^{-2} \). We need to find a physical quantity that does not match this dimensional formula. 2. **Analyzing Young's Modulus**: - **Definition**: Young's modulus (Y) is defined as the ratio of stress to strain. - **Stress**: Stress is defined as force per unit area. \[ \text{Stress} = \frac{\text{Force}}{\text{Area}} = \frac{F}{A} \] The dimension of force (F) is \( ML T^{-2} \) and the dimension of area (A) is \( L^2 \). \[ \text{Dimension of Stress} = \frac{MLT^{-2}}{L^2} = ML^{-1}T^{-2} \] - **Strain**: Strain is defined as the change in length divided by the original length, which is dimensionless. \[ \text{Strain} = \frac{\Delta L}{L} \implies \text{Dimension of Strain} = L^0 \] - Therefore, the dimension of Young's modulus is: \[ Y = \frac{\text{Stress}}{\text{Strain}} = \frac{ML^{-1}T^{-2}}{L^0} = ML^{-1}T^{-2} \] 3. **Analyzing Stress**: - As calculated above, the dimension of stress is: \[ \text{Dimension of Stress} = ML^{-1}T^{-2} \] 4. **Analyzing Strain**: - As calculated above, the dimension of strain is: \[ \text{Dimension of Strain} = L^0 \] - This shows that strain is dimensionless and does not match \( ML^{-1}T^{-2} \). 5. **Analyzing Pressure**: - **Definition**: Pressure is also defined as force per unit area. \[ \text{Pressure} = \frac{\text{Force}}{\text{Area}} = \frac{F}{A} \] - As calculated earlier, the dimension of pressure is: \[ \text{Dimension of Pressure} = ML^{-1}T^{-2} \] 6. **Conclusion**: Among the quantities analyzed, strain is the only one that does not have the dimensional formula \( ML^{-1}T^{-2} \). Therefore, the answer is strain. ### Final Answer: The physical quantity that does not represent the dimensional formula \( ML^{-1}T^{-2} \) is **strain**.

To determine which physical quantity does not have the dimensional formula \( ML^{-1}T^{-2} \), we will analyze the dimensions of Young's modulus, stress, strain, and pressure. ### Step-by-Step Solution: 1. **Understanding the Given Dimensional Formula**: The dimensional formula we are examining is \( ML^{-1}T^{-2} \). We need to find a physical quantity that does not match this dimensional formula. 2. **Analyzing Young's Modulus**: ...
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