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Which of the following is dimensionally ...

Which of the following is dimensionally correct?

A

pressure`=`energy per unit area

B

`pressure`=`energy per unit volume

C

pressure`=`force per unit volume

D

pressure `=`momentum per unit volume per unit time

Text Solution

AI Generated Solution

The correct Answer is:
To determine which of the given options is dimensionally correct, we need to analyze each option and compare its dimensions with the dimension of pressure. ### Step-by-Step Solution: 1. **Understand the Dimension of Pressure**: - Pressure is defined as force per unit area. - The dimension of force is given by \( [F] = MLT^{-2} \). - The dimension of area is given by \( [A] = L^2 \). - Therefore, the dimension of pressure \( [P] \) can be calculated as: \[ [P] = \frac{[F]}{[A]} = \frac{MLT^{-2}}{L^2} = ML^{-1}T^{-2} \] 2. **Analyze Each Option**: - **Option A: Energy per unit area**: - The dimension of energy is \( [E] = ML^2T^{-2} \). - The dimension of area is \( [A] = L^2 \). - Therefore, the dimension of energy per unit area is: \[ \frac{[E]}{[A]} = \frac{ML^2T^{-2}}{L^2} = ML^0T^{-2} = MT^{-2} \] - This is not equal to \( ML^{-1}T^{-2} \), so Option A is incorrect. - **Option B: Energy per unit volume**: - The dimension of volume is \( [V] = L^3 \). - Therefore, the dimension of energy per unit volume is: \[ \frac{[E]}{[V]} = \frac{ML^2T^{-2}}{L^3} = ML^{-1}T^{-2} \] - This matches the dimension of pressure, so Option B is correct. - **Option C: Force per unit volume**: - The dimension of force is \( [F] = MLT^{-2} \). - Therefore, the dimension of force per unit volume is: \[ \frac{[F]}{[V]} = \frac{MLT^{-2}}{L^3} = ML^{-2}T^{-2} \] - This is not equal to \( ML^{-1}T^{-2} \), so Option C is incorrect. - **Option D: Momentum per unit volume per unit time**: - Momentum is defined as \( [p] = [m][v] = MLT^{-1} \). - Therefore, the dimension of momentum per unit volume per unit time is: \[ \frac{[p]}{[V][T]} = \frac{MLT^{-1}}{L^3 \cdot T} = \frac{ML^{-2}T^{-1}}{T} = ML^{-2}T^{-2} \] - This is not equal to \( ML^{-1}T^{-2} \), so Option D is incorrect. 3. **Conclusion**: - The only option that has the same dimension as pressure is **Option B: Energy per unit volume**. ### Final Answer: **Option B** is dimensionally correct.

To determine which of the given options is dimensionally correct, we need to analyze each option and compare its dimensions with the dimension of pressure. ### Step-by-Step Solution: 1. **Understand the Dimension of Pressure**: - Pressure is defined as force per unit area. - The dimension of force is given by \( [F] = MLT^{-2} \). - The dimension of area is given by \( [A] = L^2 \). ...
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