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The capacities of two conductors are C(1...

The capacities of two conductors are `C_(1)` and `C_(2)` and their respectively potentials are `V_(1)` and `V_(2)`. If they are connected by a thin wire, then the loss of energy will be given by

A

`(C_(1)C_(2)V_(1)+V_(2))/(2(C_(1)+C_(2))`

B

`(C_(1)C_(2)V_(1)-V_(2))/(2(C_(1)+C_(2))`

C

`(C_(1)C_(2)V_(1)-V_(2))^(2)/(2(C_(1)+C_(2))`

D

`((C_(1)C_(2))(V_(1)-V_(2)))/(C_(1)+C_(2))`

Text Solution

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The correct Answer is:
d
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Knowledge Check

  • Two spherical conductors each of capacity C are charged to potetnial V and -V . These are then conneted by means of a fine wire. The loss of energy will be

    A
    zero
    B
    `1/2CV^(2)`
    C
    `CV^(2)`
    D
    `2CV^(2)`

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