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0.5 g of a mixture of K2CO3 and Li2CO3 r...

0.5 g of a mixture of `K_2CO_3` and `Li_2CO_3` requires 30 " mL of " 0.25 N Hci for neutralisaion. Calculate the percentage composition of the mixture.

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To solve the problem of determining the percentage composition of a mixture of \( K_2CO_3 \) and \( Li_2CO_3 \) that requires 30 mL of 0.25 N HCl for neutralization, we can follow these steps: ### Step 1: Calculate the molecular weight of \( K_2CO_3 \) The molecular weight of \( K_2CO_3 \) can be calculated as follows: - Potassium (K): 39 g/mol (2 atoms) - Carbon (C): 12 g/mol (1 atom) - Oxygen (O): 16 g/mol (3 atoms) ...
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