Write the electronic configuration of the following and report the number of unpaired electron in each
a. `Mn^(2+)` b.`Cr^(2+)` c`Fe^(2+)` d.`Ni^(2+)` e.`CI^(2+)` f.`Zn^(2+)` g.`Fe^(2+)` h`Na` i.`Mg` .j`Cr(3+)`

Explanation

To solve the question of writing the electronic configuration and reporting the number of unpaired electrons for the given ions and elements, we will follow these steps:

### Step-by-Step Solution:

1. **Mn²⁺ (Manganese Ion)**
- Atomic Number of Mn = 25
- For Mn²⁺, we remove 2 electrons: 25 - 2 = 23 electrons.
- Electronic Configuration: [Ar] 3d⁵
...