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Write the electronic configuration of ...

Write the electronic configuration of the following and report the number of unpaired electron in each
a. `Mn^(2+)` b.`Cr^(2+)` c`Fe^(2+)` d.`Ni^(2+)` e.`CI^(2+)` f.`Zn^(2+)` g.`Fe^(2+)` h`Na` i.`Mg` .j`Cr(3+)`

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To solve the question of writing the electronic configuration and reporting the number of unpaired electrons for the given ions and elements, we will follow these steps: ### Step-by-Step Solution: 1. **Mn²⁺ (Manganese Ion)** - Atomic Number of Mn = 25 - For Mn²⁺, we remove 2 electrons: 25 - 2 = 23 electrons. - Electronic Configuration: [Ar] 3d⁵ ...
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Knowledge Check

  • The correct order of the number of unpaired electrons in the ions Cu^(2+), Ni^(2+), Fe^(3+) , and Cr^(3+) is

    A
    `Cu^(2+) gt Ni^(2+) gt Cr^(3+) gt Fe^(3+)`
    B
    `Ni^(2+) gt Cu^(2+) gt Fe^(3+) gt Cr^(3+)`
    C
    `Fe^(3+) gt Cr^(3+) gt Ni^(2+) gt Cu^(2+)`
    D
    `Cr^(3+) gt Fe^(3+) gt gt Ni^(2+) gt Cu^(2+)`
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