Naturally occurring boron consists of two isotopes whose atomic weight are `10.01` and `11.01`The atomic weight of natural boron is `10.81` Calculate the percentage of each isotope in natural boron

Explanation

Let the percentage of the isotope be a percentage of the second isotope will be `100 - a `
`10.81 = ((a xx 10.01) + (100 - a) xx 11.01)/(100)`
On solving we get
`a = 20,(100 - a) = 80`