Home
Class 11
CHEMISTRY
Assertion: Compressibility factor (Z) fo...

Assertion: Compressibility factor `(Z)` for non ideal gases is always greater than `1`.
Reason: Non-ideal gases always exert higher pressure than expected.

A

If both (`A`) and (`R`) are correct and (`R`) is the correct explanation of (`A`).

B

If both (`A`) and (`R`) are correct, but (`R`) is not the correct explanation of (`A`).

C

If (`A`) is correct, but (`R`) is incorrect.

D

Both (`A`) and (`R`) are incorrect.

Text Solution

AI Generated Solution

The correct Answer is:
To solve the assertion and reasoning question, we will analyze both the assertion and the reason provided. ### Step-by-Step Solution: 1. **Understanding the Assertion**: - The assertion states that the compressibility factor \( Z \) for non-ideal gases is always greater than 1. - The compressibility factor \( Z \) is defined as: \[ Z = \frac{PV}{nRT} \] - For ideal gases, \( Z = 1 \). For non-ideal gases, \( Z \) can be either greater than 1 or less than 1 depending on the interactions between gas molecules. 2. **Analyzing the Compressibility Factor**: - If \( Z > 1 \), it indicates that the gas is less compressible than an ideal gas, often due to repulsive forces between molecules. - If \( Z < 1 \), it indicates that the gas is more compressible than an ideal gas, often due to attractive forces between molecules. - Therefore, the assertion that \( Z \) is always greater than 1 is incorrect. 3. **Understanding the Reason**: - The reason states that non-ideal gases always exert higher pressure than expected. - In the van der Waals equation for real gases, the pressure is modified by a term that accounts for intermolecular forces: \[ P + \frac{a n^2}{V^2} = \frac{nRT}{V - nb} \] - Here, \( a \) accounts for attractive forces, and \( b \) accounts for the volume occupied by gas molecules. - While non-ideal gases can exert higher pressure due to repulsive forces, there are conditions under which the pressure can be lower than expected due to attractive forces dominating. - Thus, the reason that non-ideal gases always exert higher pressure than expected is also incorrect. 4. **Conclusion**: - Since both the assertion and the reason are incorrect, the correct answer is that both A and R are incorrect. ### Final Answer: Both the assertion and the reason are incorrect. ---

To solve the assertion and reasoning question, we will analyze both the assertion and the reason provided. ### Step-by-Step Solution: 1. **Understanding the Assertion**: - The assertion states that the compressibility factor \( Z \) for non-ideal gases is always greater than 1. - The compressibility factor \( Z \) is defined as: \[ ...
Doubtnut Promotions Banner Mobile Dark
|

Topper's Solved these Questions

  • STATES OF MATTER

    CENGAGE CHEMISTRY ENGLISH|Exercise Exercises (Integer)|10 Videos
  • STATES OF MATTER

    CENGAGE CHEMISTRY ENGLISH|Exercise Archives (Multiple Correct)|3 Videos
  • STATES OF MATTER

    CENGAGE CHEMISTRY ENGLISH|Exercise Exercises (Single Correct)|85 Videos
  • SOME BASIC CONCEPTS AND MOLE CONCEPT

    CENGAGE CHEMISTRY ENGLISH|Exercise Archives Subjective|11 Videos
  • STOICHIOMETRY

    CENGAGE CHEMISTRY ENGLISH|Exercise Archives Subjective|33 Videos

Similar Questions

Explore conceptually related problems

Assertion : Compressibility factor for ideal gas is one. Reason : For an ideal gas PV = nRT equation is obeyed.

The compressibility factor (Z) of real gas is usually less than 1 at low temperature and low pressure because

Knowledge Check

  • Assertion : Compressibility factor (Z) is the ratio of actual molar volume of a gas to the molar volume of it , if it were an ideal gas at that temperature and pressure . Reason : At high pressure all the gases have Z lt 1 and can be easily compressed .

    A
    If both assertion and reason are true and reason is the correct explanation of assertion .
    B
    If both assertion and reason are true but reason is not the correct explanation of assertion .
    C
    If assertion is true but reason is false .
    D
    If both assertion and reason are false .
  • Similar Questions

    Explore conceptually related problems

    At a high pressure, the compressibility factor (Z) of a real gas is usually greater than one. This can be explained from van der Waals equation by neglecting the value of:

    Non-ideal gases approach ideal beheaviour under :

    The compressibility factor of gases is less than unity at STP . Therefore,

    The compressibility factor of gases is less than unity at STP . Therefore,

    For ideal gases, Z = 1 at all temperature and pressure.

    Why in the case of hydrogen and helium, the compressibility factor is always greater than 1 and increases with increase of pressure?

    A : Coefficient of performanceof a refreigerator is always greater than 1. R : Efficiencyof heat engine is greater than 1.