What volume of `O_(2)` at 2.00 atm pressure and `27^(@)C` is required to burn 10.0 g of heptane `(C_(7)H_(16))` ?
`C_(7)H_(16) + 11 O_(2) to 7 CO_(2) + 8 H_(2)O`

Explanation

To find the volume of oxygen (\(O_2\)) required to burn 10.0 g of heptane (\(C_7H_{16}\)), we will follow these steps:

### Step 1: Write the balanced chemical equation
The combustion reaction of heptane is given as:
\[ C_7H_{16} + 11 O_2 \rightarrow 7 CO_2 + 8 H_2O \]

...