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What volume of O(2) at 2.00 atm pressure...

What volume of `O_(2)` at 2.00 atm pressure and `27^(@)C` is required to burn 10.0 g of heptane `(C_(7)H_(16))` ?
`C_(7)H_(16) + 11 O_(2) to 7 CO_(2) + 8 H_(2)O`

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AI Generated Solution

To find the volume of oxygen (\(O_2\)) required to burn 10.0 g of heptane (\(C_7H_{16}\)), we will follow these steps: ### Step 1: Write the balanced chemical equation The combustion reaction of heptane is given as: \[ C_7H_{16} + 11 O_2 \rightarrow 7 CO_2 + 8 H_2O \] ...
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