When `CaCO_(3)` is heated to a high temperature, it undergoes decomposition into `CaO` and `CO_(2)` whereas it is quite stable at room temperature. The most likely explanation of its is

Options

A. The enthalpy of reaction `(DeltaH)` overweighs the term `T DeltaS` at high temperature.
B. The term `T DeltaS` overweights the enthalpy of reaction at high temperature
C. At high temperature, both enthalpy of reaction and entropy change becomes negative.
D. None of these.

Explanation

To solve the question regarding the stability of calcium carbonate (CaCO₃) at room temperature and its decomposition upon heating, we can analyze the thermodynamic principles involved.

### Step-by-Step Solution:

1. **Understanding the Reaction**:
When calcium carbonate (CaCO₃) is heated, it decomposes into calcium oxide (CaO) and carbon dioxide (CO₂):
\[
\text{CaCO}_3 (s) \rightarrow \text{CaO} (s) + \text{CO}_2 (g)
...