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Form the given data of equilibrium const...

Form the given data of equilibrium constants of the following reactions:
`CuO(s)+H_(2)(g)hArrCu(s)+H_(2)O(g),K=67`
`CuO(s)+CO(g)hArrCu(s)+CO_(2)(g),K=490`
Calculate the equilibrium constant of the reaction,
`CO_(2)(g)+H_(2)(g)hArr+CO(g)+H_(2)O(g)`

Text Solution

AI Generated Solution

To solve the problem of calculating the equilibrium constant for the reaction: \[ \text{CO}_2(g) + \text{H}_2(g) \rightleftharpoons \text{CO}(g) + \text{H}_2\text{O}(g) \] we will use the provided equilibrium constants for the following reactions: 1. \( \text{CuO}(s) + \text{H}_2(g) \rightleftharpoons \text{Cu}(s) + \text{H}_2\text{O}(g), \quad K_1 = 67 \) ...
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Knowledge Check

  • The expression for equilibrium constant, K_(c) for the following reaction is 2Cu(NO_(3))_(2(s))hArr2CuO_((s))+4NO_(2(g))+O_(2(g))

    A
    `K_(c)=([CuO_((s))]^(2)[NO_(2(g))]^(4)[O_(2(g))])/([Cu(NO_(3))_(2(s))]^(2))`
    B
    `K_(c)=([NO_(2(g))]^(4)[O_(2(g))])/([Cu(NO_(3))_(2(g))]^(2))`
    C
    `K_(c)=[NO_(2(g))]^(4)[O_(2(g))]`
    D
    `K_(c)=([CuO_((s))]^(2))/([Cu(NO_(3))_(2(g))]^(2))`

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