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At 1400 K, K( c) = 2.5 xx 10^(-3) for th...

At `1400 K, K_( c) = 2.5 xx 10^(-3)` for the reaction
`CH_(4)(g)+2H_(2)S(g)hArrCS_(2)(g)+4H_(2)(g)`
A ` 10 L` reaction vessel at `1400 K` contains `2.0 mol` of `CH_(4)`, `4.0 mol` of `H_(2)S` ,`3.0 mol` of `CS_(2)`, `3.0 mol` of `H_(2)`. In which direction does the reaction proceed to reach equilibrium?

A

Forward

B

Backward

C

May be forward or backward

D

Reaction is in equilibrium

Text Solution

AI Generated Solution

The correct Answer is:
To determine the direction in which the reaction will proceed to reach equilibrium, we need to calculate the reaction quotient (Q) and compare it with the equilibrium constant (Kc). ### Step-by-Step Solution: 1. **Write the balanced chemical equation:** \[ \text{CH}_4(g) + 2\text{H}_2\text{S}(g) \rightleftharpoons \text{CS}_2(g) + 4\text{H}_2(g) \] 2. **Identify the given quantities:** - Moles of CH₄ = 2.0 mol - Moles of H₂S = 4.0 mol - Moles of CS₂ = 3.0 mol - Moles of H₂ = 3.0 mol - Volume of the reaction vessel = 10 L 3. **Calculate the molar concentrations:** \[ \text{Concentration} = \frac{\text{Number of moles}}{\text{Volume (L)}} \] - Concentration of CH₄ = \(\frac{2.0 \, \text{mol}}{10 \, \text{L}} = 0.2 \, \text{M}\) - Concentration of H₂S = \(\frac{4.0 \, \text{mol}}{10 \, \text{L}} = 0.4 \, \text{M}\) - Concentration of CS₂ = \(\frac{3.0 \, \text{mol}}{10 \, \text{L}} = 0.3 \, \text{M}\) - Concentration of H₂ = \(\frac{3.0 \, \text{mol}}{10 \, \text{L}} = 0.3 \, \text{M}\) 4. **Write the expression for the reaction quotient (Q):** \[ Q = \frac{[\text{CS}_2][\text{H}_2]^4}{[\text{CH}_4][\text{H}_2\text{S}]^2} \] 5. **Substitute the concentrations into the Q expression:** \[ Q = \frac{(0.3)(0.3)^4}{(0.2)(0.4)^2} \] 6. **Calculate Q:** \[ Q = \frac{(0.3)(0.0081)}{(0.2)(0.16)} = \frac{0.00243}{0.032} = 0.0759 \] 7. **Compare Q with Kc:** - Given \(K_c = 2.5 \times 10^{-3} = 0.0025\) - Since \(Q = 0.0759\) and \(K_c = 0.0025\), we find that \(Q > K_c\). 8. **Determine the direction of the reaction:** - If \(Q > K_c\), the reaction will proceed in the backward direction (to the left) to reach equilibrium. ### Conclusion: The reaction will proceed in the backward direction to reach equilibrium. ---

To determine the direction in which the reaction will proceed to reach equilibrium, we need to calculate the reaction quotient (Q) and compare it with the equilibrium constant (Kc). ### Step-by-Step Solution: 1. **Write the balanced chemical equation:** \[ \text{CH}_4(g) + 2\text{H}_2\text{S}(g) \rightleftharpoons \text{CS}_2(g) + 4\text{H}_2(g) \] ...
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