Home
Class 11
CHEMISTRY
0.1mol of RNH(2)(K(b) = 5 xx 10^(-4)) is...

`0.1mol` of `RNH_(2)(K_(b) = 5 xx 10^(-4))` is mixed with `0.08mol` of `HC1` and diluted to `1L`. Calculate the `[H^(o+)]` in the solution.

A

The concentration of `H^(o+)` ion is `8 xx 10^(-11)M`.

B

The concentration of `H^(o+)` ion is `8 xx 10^(-5)M`.

C

The `pH` of solution is `9.8`

D

The `pOH` of solution is `10.2`.

Text Solution

Verified by Experts

The correct Answer is:
A, C
`{:(,CH_(3)NH_(2)+,HCIrarr,CH_(3)overset(o+)NH_(3)+,CI^(Theta)),("Initial",0.1,0.08,,),("moles",(0.1-0.08),(0.008-0.008),0.008,-),(,=0.02,=0,,):}`
Since `W_(B)` is left, so it forms basic buffer solution
`[overset(Theta)OH] = K_(b) (["Base"])/(["Salt"]) = 5xx 10^(-4) xx (0.02)/(0.08) = 1.25 xx 10^(-14)`
`[H^(o+)] = (K_(w))/([overset(Theta)OH]) = (10^(-14))/(1.25 xx 10^(-4)) = 8 xx 10^(-11)M`
`pH =- log (8 xx 10^(-11))`
`=- log2^(4) +11`
`=- 0.3 xx 4+11 = 9.8`
`pOH = 14 - 9.8 = 4.2`
Doubtnut Promotions Banner Mobile Dark
|

Topper's Solved these Questions

  • IONIC EQUILIBRIUM

    CENGAGE CHEMISTRY ENGLISH|Exercise Exercises Single Correct|121 Videos

  • IONIC EQUILIBRIUM

    CENGAGE CHEMISTRY ENGLISH|Exercise Exercises Assertion-Reasoning|36 Videos

  • IONIC EQUILIBRIUM

    CENGAGE CHEMISTRY ENGLISH|Exercise Exercises Linked Comprehension|45 Videos

  • HYDROGEN, WATER AND HYDROGEN PEROXIDE

    CENGAGE CHEMISTRY ENGLISH|Exercise Subjective Archive (Subjective)|3 Videos

  • ISOMERISM

    CENGAGE CHEMISTRY ENGLISH|Exercise Assertion-Reasoning Type|1 Videos

Similar Questions

Explore conceptually related problems

0.1 mole of CH_(3)CH (K_(b) = 5 xx 10^(-4)) is mixed with 0.08 mole of HCl and diluted to one litre. What will be the H^(+) concentration in the solution

CH_(3)NH_(2)(0.1"mole",K_(b)=5xx10^(-4)) is added to 0.08 moles of HCI and the solution is diluted to one litre. The resulting hydrogen ion concentration is

Knowledge Check

  • The rate of formation of a dimer in a second order dimerisation reaction is 9.1 xx 10^(-6) mol L^(-1)s^(1) at 0.01 mol L^(-1) monomer concentration. Calculate the rate consant for the reaction.

    A
    `9.1 xx 10^(-2) L mol^(-1) s^(-1)`
    B
    `9.1 xx 10^(-6) mol^(-1) s^(-1)`
    C
    `3 xx 10^(-4) L mol^(-1) s^(-1)`
    D
    `27.3 xx 10^(-2) L mol^(-1) s^(-1)`

    • Similar Questions

    Explore conceptually related problems

    1 mol of C_(6)H_(6) , 0.1 mol of HNO_(3) and 0.05 mol of H_(2)SO_(4) are mixed and water is added to the mixture . pH of the solution , if the final volume is 1 L , is

    In equalitative analysis, cations of graph II as well as group IV both are precipitated in the form of sulphides. Due to low value of K_(sp) of group II sulphides, group reagent is H_(2)S in the presence of dil. HC1 , and due to high value of K_(sp) of group IV sulphides, group reagent is H_(2)S in the presence of NH_(4)OH and NH_(4)C1 . In a solution containing 0.1M each of Sn^(2+), Cd^(2+) , and Ni^(2+) ions, H_(2)S gas is passed. K_(sp) of SnS = 8 xx 10^(-29), K_(sp) of CdS = 10^(-28), K_(sp) of NiS - 3 xx 10^(-21) K_(1) of H_(2)S = 1 xx 10^(-7), K_(2) of H_(2)S = 1 xx 10^(-14) If 0.1M HC1 is mixed in the solution containing only 0.1 M Cd^(2+) ions and saturated with H_(2)S , then [Cd^(2+)] remaining in the solution after CdS stopes to precipitate is:

    Calculate the hydrolysis constant and degree of hydrolysis of NH_(4) Cl" in " 0.1 M solution . K_(b) = 1.8 xx 10^(-5) . Calculate the concentration of H^(+) ions in the solution .

    A mixture of 0.1 mol of Na_(2)O and 0.1 mol of BaO is dissolved in 1000 g of H_(2)O . Calculate the vapour pressure of solution at 373 K .

    For the reaction k_(1) = 1.78 xx 10^(-3)s^(-1) and k_(2) = 5.8 xx 10^(-5)s^(-1) for the initial concentration of [Cr(H_(2)O)_(4)Cl_(2)]^(o+) is 0.0174 mol L^(-) at 0^(@)C . Calculate the value of time at which the concentration of [Cr(H_(2)O)_(5)Cl]^(2+) is maximum.

    It is given that 0.001 mol each of Cd^(2+) and Fe^(2+) ions are contained in 1.0L of 0.02M HC1 solution. This solutions is now saturated with H_(2)S gas at 25^(@)C . a. Determine whether or not each of these ions will be precipitated as sulphide? b. How much Cd^(2+) ions remains in the solution at equilibrium? K_(1)(H_(2)S) = 1.0 xx 10^(-7), K_(2) (H_(2)S) = 1.0 xx 10^(-14) : ltbRgt K_(sp) (CdS) = 8 xx 10^(-27): K_(sp) (FeS) = 3.7 xx 10^(-19) .

    The rate of formation of a dimer in a second order dimerization reaction is 9.5 xx 10^(-5) mol L^(-1) s^(-1) at 0.01 mol L^(-1) monomer concentration. Calculate the rate constant.

    Home
    Profile