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At 90^(@)C, pure water has [H(3)O^(o+)] ...

At `90^(@)C`, pure water has `[H_(3)O^(o+)] = 10^(-7)mol L^(-1)`. What is the value of `K_(w)`at `90^(@)C`?

A

`10^(-6)`

B

`10^(-12)`

C

`10^(-14)`

D

`10^(-8)`

Text Solution

Verified by Experts

The correct Answer is:
B
`[H_(3)O^(o+)] = 10^(-6) = [overset(Theta)OH]`
Because in pure water, `[H_(3)O^(o+)] = [overset(Theta)OH]`
`K_(w) = [H_(3)O^(o+)] = [overset(Theta)OH]`
`= 10^(-6) xx 10^(-6)`
`= 10^(-12)`
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At 90^(@)C pure water has [H_(3)O^(+)] as 10^(-6) mol L^(-1) . What is the value of K_(w) at 90^(@)C ?

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Knowledge Check

  • At 80 ^(@ ) C , pure distilled water has [H_3O^(+) ]= 1 xx 10 ^(-6) " mol " L^(-1) The value of K_w at this temperature will be

    A
    `1 xx 10 ^(-6)`
    B
    ` 1 xx 10 ^(-12)`
    C
    ` 1 xx 10 ^(-14)`
    D
    ` 1 xx 10 ^(-5)`

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    A
    5
    B
    11
    C
    `0.2`
    D
    72

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