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A crystal is made of particles X,Y and Z.X form fcc packing . Y occupies all the octahedral void of X and Z occupies all the tetrahedral voids of X . If all the particles along one body diagonal are removed then the formula of the crystal would be:

A

`XYZ_(2)`

B

`X_(2)YZ_(2)`

C

`X_(8)Y_(4)Z_(5)`

D

`X_(5)Y_(4)Z_(8)`

Text Solution

Verified by Experts

The correct Answer is:
D
For fcc, number of `X` atoms `= 4//"unit cell"`
Number of `TVs = 8Z`
Number of `OVs = 4Y`
Number of atoms removed along one body diagonal `= 2X ("corner")` and `2Z("TVs")` are `1Y` (OV at body centre)
`:.` Number of `X` atoms left `= 4 - (2 xx 1/8) = 15/4`
Number of `Y` atoms left `= 4 - (1 xx 1) = 3`
Number of `Z` atoms left `= 8 - (2 xx 1) = 6`
The simplest formula `= X_(15/4)Y_(3)Z_(6) rArr X_(15)Y_(12)Z_(24)`
`rArr X_(5)Y_(4)Z_(8)`
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