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Calculate the mole fraction of solute in...

Calculate the mole fraction of solute in a dilute aqueous solution from which ice begins to separate out at `-0.46^(@)C`. (`K_(f)` of `H_(2)O` =`1.86 K m^(-1)`)

Text Solution

Verified by Experts

`DeltaT_(f)=K_(f) xx m rArr m=(DeltaT_(f))/K_(f)=(0-(0-0.46))/1.86 = 0.46/1.86=0.247 m`
Use the relation,
`m=(n_(2)xx1000)/(n_(1)xxMw_(1))`
`:.n_(2)/n_(1)=chi_(2)=(m xx Mw_(1))/1000`
=`(0.247 xx 18)/1000`
`=0.004`
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Knowledge Check

  • Complete the following statements by selecting the correct alternative from the choices given : An aqueous solution of urea freezes at - 0.186^(@)C, K_(f) for water = 1.86 K kg. mol^(-1),K_(b) for water = 0.512 "K kg mol"^(-1) . The boiling point of urea solution will be :

    A
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    B
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    C
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    D
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