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If for a sucrose, elevation in boiling p...

If for a sucrose, elevation in boiling point is `1.0^(@)C`, then what will be the boiling point of `NaCl` solution for same molal concentration?

A

`1.0^(@)C`

B

`2.0^(@)C`

C

`3.0^(@)C`

D

`4.0^(@)C`

Text Solution

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The correct Answer is:
To solve the problem, we need to understand the concept of boiling point elevation and how it relates to the Van't Hoff factor for different solutes. ### Step-by-Step Solution: 1. **Understand the given data**: We know that for a sucrose solution, the elevation in boiling point (ΔTb) is 1.0°C. Sucrose is a non-electrolyte, meaning it does not dissociate into ions when dissolved in a solvent. Therefore, its Van't Hoff factor (i) is 1. 2. **Recall the formula for boiling point elevation**: The boiling point elevation can be calculated using the formula: \[ \Delta T_b = i \cdot K_b \cdot m \] where: - \( \Delta T_b \) = elevation in boiling point - \( i \) = Van't Hoff factor (number of particles the solute dissociates into) - \( K_b \) = ebullioscopic constant of the solvent - \( m \) = molality of the solution 3. **Apply the formula for sucrose**: For the sucrose solution, we have: \[ 1.0 = 1 \cdot K_b \cdot m \] This means that \( K_b \cdot m = 1.0 \). 4. **Consider the NaCl solution**: Now, we need to find the boiling point elevation for a NaCl solution at the same molal concentration. NaCl is an electrolyte and dissociates into two ions: Na⁺ and Cl⁻. Therefore, its Van't Hoff factor (i) is 2. 5. **Apply the formula for NaCl**: For the NaCl solution, the boiling point elevation can be expressed as: \[ \Delta T_b = 2 \cdot K_b \cdot m \] Since we know \( K_b \cdot m = 1.0 \) from the sucrose solution, we can substitute this into the equation: \[ \Delta T_b = 2 \cdot 1.0 = 2.0 \] 6. **Determine the boiling point of the NaCl solution**: The boiling point of the solution (Tb) can be calculated as: \[ T_b = T_{b, \text{pure solvent}} + \Delta T_b \] Assuming the boiling point of the pure solvent (water) is 100°C: \[ T_b = 100°C + 2.0°C = 102.0°C \] ### Final Answer: The boiling point of the NaCl solution at the same molal concentration is **102.0°C**. ---

To solve the problem, we need to understand the concept of boiling point elevation and how it relates to the Van't Hoff factor for different solutes. ### Step-by-Step Solution: 1. **Understand the given data**: We know that for a sucrose solution, the elevation in boiling point (ΔTb) is 1.0°C. Sucrose is a non-electrolyte, meaning it does not dissociate into ions when dissolved in a solvent. Therefore, its Van't Hoff factor (i) is 1. 2. **Recall the formula for boiling point elevation**: ...
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