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Two platinum electrodes were immersed i...

Two platinum electrodes were immersed in a solution of `CuSO_(4)` and electric current was passed through the solution. After some time, it was found that colour of `CuSO_(4)` disappeared with evolution of gas at the electrode. The colourless solution contains.

A

Platinum sulphate

B

Copper hydroxide

C

Copper sulphate

D

Sulphuric acid

Text Solution

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The correct Answer is:
To solve the question regarding the electrolysis of a copper sulfate (CuSO₄) solution using platinum electrodes, we can follow these steps: ### Step-by-Step Solution: 1. **Understanding Electrolysis**: When electric current passes through the copper sulfate solution, it causes the ions in the solution to migrate towards the electrodes. The copper ions (Cu²⁺) will move towards the cathode (negative electrode), while the sulfate ions (SO₄²⁻) and water will interact at the anode (positive electrode). 2. **Identifying the Reactions**: - **At the Cathode**: The Cu²⁺ ions will gain electrons (reduction) to form solid copper (Cu). The reaction can be represented as: \[ \text{Cu}^{2+} + 2e^- \rightarrow \text{Cu (s)} \] - **At the Anode**: Water will be oxidized to produce oxygen gas (O₂) and hydrogen ions (H⁺). The reaction can be represented as: \[ 2\text{H}_2\text{O} \rightarrow \text{O}_2 + 4\text{H}^+ + 4e^- \] 3. **Observing Changes in the Solution**: As the electrolysis proceeds, the blue color of the copper sulfate solution fades. This is because the Cu²⁺ ions are being reduced and deposited as solid copper on the cathode, leading to a decrease in the concentration of Cu²⁺ ions in the solution. 4. **Formation of New Species**: The H⁺ ions produced at the anode combine with the remaining sulfate ions in the solution. This results in the formation of sulfuric acid (H₂SO₄): \[ \text{H}^+ + \text{SO}_4^{2-} \rightarrow \text{H}_2\text{SO}_4 \] 5. **Conclusion**: The colorless solution that remains after the electrolysis contains sulfuric acid (H₂SO₄) due to the combination of H⁺ ions and SO₄²⁻ ions. ### Final Answer: The colorless solution contains **sulfuric acid (H₂SO₄)**. ---

To solve the question regarding the electrolysis of a copper sulfate (CuSO₄) solution using platinum electrodes, we can follow these steps: ### Step-by-Step Solution: 1. **Understanding Electrolysis**: When electric current passes through the copper sulfate solution, it causes the ions in the solution to migrate towards the electrodes. The copper ions (Cu²⁺) will move towards the cathode (negative electrode), while the sulfate ions (SO₄²⁻) and water will interact at the anode (positive electrode). 2. **Identifying the Reactions**: - **At the Cathode**: The Cu²⁺ ions will gain electrons (reduction) to form solid copper (Cu). The reaction can be represented as: ...
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