Home
Class 12
CHEMISTRY
The addition of a crystal of I(2) to NaB...

The addition of a crystal of `I_(2)` to `NaBr` turns the solution violet.

Text Solution

AI Generated Solution

The correct Answer is:
To solve the question regarding the addition of a crystal of iodine (I₂) to sodium bromide (NaBr) and the resulting violet color, we can break down the explanation into several steps. ### Step-by-Step Solution: 1. **Understanding the Components**: - Sodium bromide (NaBr) is an ionic compound made up of sodium ions (Na⁺) and bromide ions (Br⁻). - Iodine (I₂) is a diatomic molecule that is known for its characteristic violet color when dissolved in a solvent. 2. **Addition of Iodine to NaBr**: - When a crystal of iodine is added to a solution of sodium bromide, the iodine does not react with the sodium bromide. This is because iodine is less reactive compared to bromine and cannot displace bromine from its compound. 3. **Color Observation**: - The violet color observed in the solution is due to the presence of iodine (I₂) itself. Iodine has a natural violet color, and when it is dissolved in the solution, it imparts this color to the solution. 4. **Comparison with Other Halides**: - If sodium fluoride (NaF) or sodium chloride (NaCl) were used instead of sodium bromide, the same violet color would be observed. This is because iodine cannot displace any of the other halogens (F or Cl) from their respective salts due to its lower reactivity. 5. **Conclusion**: - Therefore, the statement that the addition of iodine to sodium bromide turns the solution violet is true. The solution remains violet because iodine does not react with sodium bromide and retains its characteristic color.
To solve the question regarding the addition of a crystal of iodine (I₂) to sodium bromide (NaBr) and the resulting violet color, we can break down the explanation into several steps. ### Step-by-Step Solution: 1. **Understanding the Components**: - Sodium bromide (NaBr) is an ionic compound made up of sodium ions (Na⁺) and bromide ions (Br⁻). - Iodine (I₂) is a diatomic molecule that is known for its characteristic violet color when dissolved in a solvent. ...
Doubtnut Promotions Banner Mobile Dark
|

Topper's Solved these Questions

  • ELECTROCHEMISTRY

    CENGAGE CHEMISTRY ENGLISH|Exercise Archieves (Linked Comprehension )|13 Videos

  • ELECTROCHEMISTRY

    CENGAGE CHEMISTRY ENGLISH|Exercise Archieves Multiple Correct Ansers|2 Videos

  • ELECTROCHEMISTRY

    CENGAGE CHEMISTRY ENGLISH|Exercise Exercisefill In The Blanks|25 Videos

  • D AND F BLOCK ELEMENTS

    CENGAGE CHEMISTRY ENGLISH|Exercise Archives Subjective|29 Videos

  • GENERAL PRINCIPLES AND PROCESS OF ISOLATION OF ELEMENTS

    CENGAGE CHEMISTRY ENGLISH|Exercise Archives (Subjective)|14 Videos

Similar Questions

Explore conceptually related problems

State True or false The addition of Br_(2) to NaI turns the solution violet.

On the addition of a solution containing CrO_(4)^(2-) ions to the solution of Ba^(2+), Sr^(2+) and Ca^(2+) ions, the precipitate obtained first will be of:

The addition of CaCl_(2) crystal to KCl crystal a. Lowers the density of the KCl crystal b. Raises the density of the KCl crystal c. Does not affect the density of the KCl crystal d. Increases the Frenkel defects of the KCl crystal

The addition of CaCl_(2) to a KCl crystal lowers the density of the KCl crystal.

The pH of a dilute solution of acetic acid was found to be 4.3 . The addition of a small crystal of sodium acetate will cause pH to

When a crystal of a solute are introduced into a saturated solution, the excess of solute crystallizes out and solution remains saturated (True/False).

The additive inverse of 5+7i is

Addition of a solute to pure water causes

The addition of NaOH to Cr^(3+) solution produces the precipitate of

Addition of NaOH on Zn^(2+) ion gives a white ppt. which on addition of excess of NaOH which dissolves . In this solution Zn exists in

Home
Profile