An organic compound (A) `(C_(10)H_(20))` on reductive ozonolysis gives `2-` methyl butanal. Based on this information, answer the following question.
1. Compound (A) is

Options

A.
B.
C.
D.

Explanation

To determine the structure of the organic compound (A) with the molecular formula \( C_{10}H_{20} \) that yields 2-methylbutanal upon reductive ozonolysis, we can follow these steps:

### Step 1: Understand the Reaction
Reductive ozonolysis of alkenes typically breaks the double bond and produces aldehydes or ketones. Since we are given that the product is 2-methylbutanal, we need to identify a symmetric alkene that can yield this product.

### Step 2: Identify the Product Structure
The structure of 2-methylbutanal can be represented as follows:
- It has a total of 5 carbon atoms.
- The structure can be drawn as:
\[ CH_3-CH_2-CH(CH_3)-CHO \]
This indicates that the product has a branched structure with a carbonyl group (aldehyde).

### Step 3: Determine the Alkene Structure
To produce 2-methylbutanal from ozonolysis, the alkene must be symmetric. The ozonolysis will split the double bond and form two identical aldehyde molecules.

A suitable alkene that fits this requirement is:
\[ CH_3-CH_2-CH=CH-CH_2-CH(CH_3)-CH_2-CH_3 \]
This compound has the following structure:
- It contains a double bond between the second and third carbon atoms.
- It has a total of 10 carbon atoms, which matches the formula \( C_{10}H_{20} \).

### Step 4: Verify the Structure
When this alkene undergoes reductive ozonolysis, the double bond will break, and we will get two moles of 2-methylbutanal:
- The reaction can be summarized as:
\[ CH_3-CH_2-CH=CH-CH_2-CH(CH_3)-CH_2-CH_3 \xrightarrow{O_3} 2 \times CH_3-CH_2-CH(CH_3)-CHO \]

### Conclusion
Thus, the compound (A) is:
\[ \text{Compound (A) is } 2,4-dimethyl-1-hexene. \]