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The H-O-H bond angle in the water molecu...

The `H-O-H` bond angle in the water molecule is `105^@` , the`H -O` bond distance being `0.94 Å`, The dipole moment for the moelcule is `1.85D`. Calculate the charge on the oxygen atom .

A

`2 xx 10^(-10)` esu

B

`3.28 xx 10^(-10)` esu

C

`3.21 xx 10^(-10)` esu

D

`1.602 xx 10^(-19)` esu

Text Solution

AI Generated Solution

The correct Answer is:
To calculate the charge on the oxygen atom in a water molecule (H₂O), we can follow these steps: ### Step 1: Understand the relationship between dipole moment, charge, and distance The dipole moment (μ) is given by the formula: \[ \mu = q \times d \] where \( q \) is the charge and \( d \) is the distance between the charges. ### Step 2: Convert the given values to appropriate units - The dipole moment is given as 1.85 D (Debye). To convert this to ESU cm: \[ 1 \text{ D} = 3.3356 \times 10^{-30} \text{ C m} = 3.3356 \times 10^{-18} \text{ ESU cm} \] Thus, \[ \mu = 1.85 \text{ D} = 1.85 \times 3.3356 \times 10^{-18} \text{ ESU cm} \] \[ \mu \approx 6.17 \times 10^{-18} \text{ ESU cm} \] - The bond distance (H-O) is given as 0.94 Å. Convert this to cm: \[ 0.94 \text{ Å} = 0.94 \times 10^{-8} \text{ cm} \] ### Step 3: Calculate the charge using the dipole moment formula Using the dipole moment formula: \[ \mu = q \times d \] We can rearrange this to find the charge \( q \): \[ q = \frac{\mu}{d} \] Substituting the values we have: \[ q = \frac{6.17 \times 10^{-18} \text{ ESU cm}}{0.94 \times 10^{-8} \text{ cm}} \] ### Step 4: Perform the calculation Calculating the above expression: \[ q \approx \frac{6.17 \times 10^{-18}}{0.94 \times 10^{-8}} \] \[ q \approx 6.57 \times 10^{-10} \text{ ESU} \] ### Step 5: Considering the two O-H bonds in H₂O Since there are two O-H bonds in a water molecule, the total charge on the oxygen atom would be: \[ \text{Total charge on O} = 2 \times q \] Thus: \[ \text{Total charge on O} = 2 \times 6.57 \times 10^{-10} \text{ ESU} \] \[ \text{Total charge on O} \approx 1.314 \times 10^{-9} \text{ ESU} \] ### Final Answer The charge on the oxygen atom in the water molecule is approximately \( 1.314 \times 10^{-9} \text{ ESU} \). ---
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