Acidic strength order `CI_(2)O_(7) gtSO_(3) gtP_(4) O_(10)` .

Explanation

To determine the order of acidic strength among the compounds \( Cl_2O_7 \), \( SO_3 \), and \( P_4O_{10} \), we will analyze the oxidation states of the central atoms in each compound. The general principle is that the higher the oxidation state of the central atom, the stronger the acid.

### Step 1: Calculate the oxidation state of chlorine in \( Cl_2O_7 \)

The formula for calculating the oxidation state is:
\[ \text{Oxidation state} + (\text{number of oxygen atoms} \times \text{oxidation state of oxygen}) = 0 \]

For \( Cl_2O_7 \):
- Let the oxidation state of chlorine be \( x \).
- There are 2 chlorine atoms and 7 oxygen atoms.

Setting up the equation:
\[ 2x + 7(-2) = 0 \]
\[ 2x - 14 = 0 \]
\[ 2x = 14 \implies x = +7 \]

### Step 2: Calculate the oxidation state of sulfur in \( SO_3 \)

For \( SO_3 \):
- Let the oxidation state of sulfur be \( y \).
- There are 1 sulfur atom and 3 oxygen atoms.

Setting up the equation:
\[ y + 3(-2) = 0 \]
\[ y - 6 = 0 \]
\[ y = +6 \]

### Step 3: Calculate the oxidation state of phosphorus in \( P_4O_{10} \)

For \( P_4O_{10} \):
- Let the oxidation state of phosphorus be \( z \).
- There are 4 phosphorus atoms and 10 oxygen atoms.

Setting up the equation:
\[ 4z + 10(-2) = 0 \]
\[ 4z - 20 = 0 \]
\[ 4z = 20 \implies z = +5 \]

### Step 4: Compare the oxidation states

Now we have the oxidation states:
- \( Cl_2O_7 \): +7
- \( SO_3 \): +6
- \( P_4O_{10} \): +5

### Step 5: Determine the order of acidic strength

Since the acidic strength increases with the oxidation state of the central atom, we can arrange the compounds in order of acidic strength:
\[ Cl_2O_7 > SO_3 > P_4O_{10} \]

### Conclusion

The order of acidic strength is indeed \( Cl_2O_7 > SO_3 > P_4O_{10} \), confirming the given statement is correct.

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