`CO_(2)` and `N_(3)^(Theta)` have sane bond order and same shape .

Answer

To determine whether the statement that CO₂ (carbon dioxide) and N₃⁻ (azide ion) have the same bond order and same shape is correct, we can analyze both molecules step by step.

### Step 1: Analyze the structure of CO₂
- **Molecular Formula**: CO₂ consists of one carbon atom and two oxygen atoms.
- **Lewis Structure**: The Lewis structure of CO₂ shows that carbon forms a double bond with each oxygen atom. Thus, the structure can be represented as O=C=O.
- **Shape**: The shape of CO₂ is linear due to the arrangement of the electron pairs around the carbon atom.
- **Bond Order**: The bond order is calculated as the number of bonds between two atoms divided by the number of bond groups. In CO₂, there are two double bonds, so the bond order is 2.

### Step 2: Analyze the structure of N₃⁻
- **Molecular Formula**: N₃⁻ consists of three nitrogen atoms and has a net charge of -1.
- **Lewis Structure**: The azide ion can be represented as N=N=N⁻. The structure shows that there are two double bonds between the nitrogen atoms.
- **Shape**: The azide ion is also linear in shape, similar to CO₂.
- **Bond Order**: The bond order for N₃⁻ can be calculated similarly. There are two bonds (double bonds) between the nitrogen atoms, leading to a bond order of 2.

### Step 3: Compare the bond order and shape
- **Bond Order**: Both CO₂ and N₃⁻ have a bond order of 2.
- **Shape**: Both molecules are linear in shape.

### Conclusion
Since both CO₂ and N₃⁻ have the same bond order (2) and the same shape (linear), the statement is correct.

### Final Answer
The statement that CO₂ and N₃⁻ have the same bond order and same shape is **true**.

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