What is the molarity of `H_2O_2` of the `11.2V` (volume strength)?

Explanation

To find the molarity of hydrogen peroxide (H₂O₂) given its volume strength of 11.2, we can follow these steps:

### Step 1: Understand Volume Strength
Volume strength indicates how many liters of oxygen gas (O₂) are produced by 1 liter of the solution at standard temperature and pressure (STP). In this case, an 11.2 volume strength means that 1 liter of H₂O₂ will produce 11.2 liters of O₂.

### Step 2: Calculate Moles of O₂
At STP, 1 mole of gas occupies 22.4 liters. Therefore, we can calculate the number of moles of O₂ produced from the 11.2 liters:
\[ \text{Moles of O₂} = \frac{\text{Volume of O₂}}{\text{Molar Volume}} = \frac{11.2 \text{ L}}{22.4 \text{ L/mol}} = 0.5 \text{ moles} \]

### Step 3: Write the Decomposition Reaction
The decomposition of hydrogen peroxide can be represented by the following balanced equation:
\[ 2 \text{H₂O₂} \rightarrow 2 \text{H₂O} + \text{O₂} \]
From the equation, we see that 2 moles of H₂O₂ produce 1 mole of O₂.

### Step 4: Calculate Moles of H₂O₂
From the stoichiometry of the reaction, we can find the moles of H₂O₂ needed to produce 0.5 moles of O₂:
\[ \text{Moles of H₂O₂} = 0.5 \text{ moles O₂} \times 2 = 1 \text{ mole of H₂O₂} \]

### Step 5: Calculate Molarity of H₂O₂
Molarity (M) is defined as the number of moles of solute per liter of solution. Since we have 1 mole of H₂O₂ in 1 liter of solution, the molarity is:
\[ \text{Molarity of H₂O₂} = \frac{\text{Moles of H₂O₂}}{\text{Volume of solution in liters}} = \frac{1 \text{ mole}}{1 \text{ L}} = 1 \text{ M} \]

### Final Answer
The molarity of H₂O₂ with a volume strength of 11.2 is **1 M**.

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