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Deuterium is an isotope of hydrogen....

Deuterium is an isotope of hydrogen.

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### Step-by-Step Solution: 1. **Understanding Isotopes**: - Isotopes are variants of a chemical element that have the same number of protons (atomic number) but different numbers of neutrons, leading to different atomic masses. 2. **Identifying Hydrogen Isotopes**: - Hydrogen has three known isotopes: - **Protium (¹H)**: This isotope has 1 proton and 0 neutrons. Its atomic mass is 1. - **Deuterium (²H)**: This isotope has 1 proton and 1 neutron. Its atomic mass is 2. - **Tritium (³H)**: This isotope has 1 proton and 2 neutrons. Its atomic mass is 3. 3. **Confirming the Statement**: - The statement "Deuterium is an isotope of hydrogen" is true because deuterium (²H) has the same atomic number (1) as hydrogen but a different atomic mass (2), which qualifies it as an isotope. 4. **Conclusion**: - Therefore, the statement is correct: Deuterium is indeed an isotope of hydrogen.
### Step-by-Step Solution: 1. **Understanding Isotopes**: - Isotopes are variants of a chemical element that have the same number of protons (atomic number) but different numbers of neutrons, leading to different atomic masses. 2. **Identifying Hydrogen Isotopes**: - Hydrogen has three known isotopes: - **Protium (¹H)**: This isotope has 1 proton and 0 neutrons. Its atomic mass is 1. ...
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Deuterium is the isotope of hydrogen of mass number 2 , with a proton and a neutron in its nucleus. The chemistry of deuterium is nearly identical to the chemistry of hydrogen, except that C-D bond is slightly (5.0 "KJ" //"mole") stonger than the C-H bond. Reaction rates tend to be slower if a C-D bond as opposed to a C-H bond is broken in a rate limiting step. This effect on the rate is called a kinetic isotope effect. CH_(3)-overset(O) overset(||)(C)-CH_(3)overset(D_(2)O,D^(+))toX

At a temperature of 0 K , the total energy of a gaseous diatomic molecule AB is approximately given by: E=E_(o)+E_(vib) where E_(o) is the electronic energy of the ground state, and E_(vib) is the vibrational energy. Allowed values of the vibrational energies are given by the expression: E_(vid)=(v-1/2)epsilon " " v=0, 1, 2, ....... " " epsilon=h/(2pi)sqrt(k/mu) " " mu(AB)=(m_(A)m_(B))/(m_(A)+m_(B)) where h is the planck's constant, is the vibration quantum number, k is the force constant, and is the reduced mass of the molecule. At 0K , it may be safely assumed that is zero, and E_(o) and k are independent of isotopic substitution in the molecule. Deuterium, D, is an isotope of hydrogen atom with mass number 2 . For the H_(2) molecule, k is 575.11 N m^(-1) , and the isotopic molar masses of H and D are 1.0078 and 2.0141 g mol^(-1) , respectively. At a temperature of 0K : epsilon_(H_(2))=1.1546 epsilon_(HD) and epsilon_(D_(2))=0.8167 epsilon_(HD) ul("Calculate") the dissociation energy, DeltaE , in eV of a hydrogen molecule in its ground state such that both H atoms are produced in their ground states.

Knowledge Check

  • Tritium is an isotope of hydrogen whose nucleus triton decays , it would transform into He^3 nucleus . This does not happen .This is because

    A
    Triton energy is less than that of a `He^3` nucleus
    B
    The electron created in the beta decay process cannot remain in the nucleus
    C
    both the neutrons in triton have a decay simultaneously resulting in a nucleus with 3 protons which is not a `He^3` nucleus .
    D
    because free neutrons decay due to external perturbations which is absent in a triton nucleus .

  • A deuterium is

    A
    an electron with a positive charge
    B
    a nucleus having two protons
    C
    a nucleus containing a neutron and two protons
    D
    a nucleus containing a neutron and a proton.

  • Which one of the following is not an isotope of hydrogen ?

    A
    Protium
    B
    Ortho- para hydrogen
    C
    Deuterium
    D
    Tritium

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