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When an inorganic compund X having 3c-2e...

When an inorganic compund X having `3c-2e^(-)` as well as `2c^(-1)-2e^(-1)` bonds react with `NH_(3)` gas at a certain temperature, gives a compound Y, isostuctural with benzene. Compound X with ammonia at a hight temperature produces a substance Z, then

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Inorganic graphite `(Z)` is boron nitrate. Since diborane reacts with ammonia at very high temperature to give inorganic graphite `(X)` is diborane, `B_(2)H_(6)`. Diborane contains both `(3c, 2e)` and `(2c, 2e)` bonds.
`B_(2) H_(6) + NH_(3) rarr underset("Borazine (Y)") (B_(3) N_(3) H_(6))`
Borazine is isostructural with benzene, `C_(6) H_(6)`. Hence, `(X)` is diborane, `H_(2) H_(6) , (Y)` is borazine, `B_(3) N_(3) H_(6)` and `(Z)` is boron nitrate `(BN)_(x)`.
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Knowledge Check

  • A compound X, of boron reacts with NH_(3) on heating to give another compound Y which is called inorganic benzene. The compound X can be prepared by treating and Y are represented by the formula.

    A
    `B_(2)H_(6), B_(3)N_(3)H_(6)`
    B
    `B_(2)O_(3),B_(3)N_(3)H_(6)`
    C
    `BF_(3),B_(3)N_(3)H_(6)`
    D
    `B_(3)N_(3)H_(6), B_(2)H_(6)`