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Boron always forms covalent compound. ...

Boron always forms covalent compound.
The small size of `B^(3+)` favours formation of covalent compound.

A

If both `(A)` are correct and `( R)` is the correct explanation of `(A)`.

B

If both `(A)` and `( R)` are correct but `( R)` is not the correct explanation of `(A)`.

C

If `(A)` is correct, but `( R)` is incorrect.

D

If `(A)` is incorrect, but `( R)` is correct.

Text Solution

Verified by Experts

The correct Answer is:
A

The sum of `IE_(1) + IE_(3)` for `B` is very high and `B^(3+)` ion is not known and boron always forms covalent compounds.
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