Write two resonance structure of `N_2 O` that satisfy the octet rule.

Explanation

To find two resonance structures of \( N_2O \) that satisfy the octet rule, we will follow these steps:

### Step 1: Count the total number of valence electrons
- Nitrogen (N) has 5 valence electrons, and oxygen (O) has 6 valence electrons.
- For \( N_2O \), we have:
\[ 2 \times 5 \text{ (for N)} + 6 \text{ (for O)} = 10 + 6 = 16 \text{ valence electrons} \]
...