Number of `sigma` and `pi` bonds present in sulphuric acid molecule is ____ and ____ respectively.

Answer

To determine the number of sigma (σ) and pi (π) bonds in a sulfuric acid molecule (H₂SO₄), we can follow these steps:

### Step 1: Identify the Structure of Sulfuric Acid
Sulfuric acid has the molecular formula H₂SO₄. In this molecule, sulfur (S) is the central atom, bonded to four oxygen (O) atoms.

### Step 2: Draw the Lewis Structure
1. Sulfur has 6 valence electrons (as it is in Group 16).
2. Each oxygen atom has 6 valence electrons, and there are four oxygen atoms, contributing a total of 24 electrons.
3. Hydrogen contributes 1 electron each, and there are 2 hydrogen atoms, contributing a total of 2 electrons.
4. The total number of valence electrons in H₂SO₄ is 6 (S) + 24 (O) + 2 (H) = 32 electrons.

The Lewis structure of sulfuric acid can be drawn as follows:
- Sulfur is in the center, double-bonded to two oxygen atoms (forming two π bonds), and single-bonded to two hydroxyl (OH) groups (forming two σ bonds).

### Step 3: Count the Sigma Bonds
1. Each single bond (S-O in the OH groups) is a sigma bond.
2. Each double bond (S=O) consists of one sigma bond and one pi bond.
3. In total:
- 2 S-O bonds from the hydroxyl groups (2 σ bonds)
- 2 S=O double bonds (2 σ bonds)

Thus, the total number of sigma bonds is:
- 2 (from OH) + 2 (from S=O) = 4 σ bonds.

### Step 4: Count the Pi Bonds
1. Each double bond (S=O) contributes one pi bond.
2. Since there are 2 double bonds, the total number of pi bonds is:
- 2 (from S=O).

### Final Count
- Total number of sigma bonds: 6
- Total number of pi bonds: 2

### Answer
The number of sigma bonds present in sulfuric acid is **6**, and the number of pi bonds is **2**.

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