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Bond dissociation energy of F(2) is less...

Bond dissociation energy of `F_(2)` is less that of `Cl_(2)` give reason.

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Atomic size of `F` atom is less than `Cl` ,hence bond length `F-F` is less than `Cl-Cl`. Thus the `lp-lp` repulsion in `F-F` molecule is much larger than `Cl-Cl` molecules . Hence `F-F` bond is weaker than `Cl-Cl` bond dissociation energy of `F_(2)` is less than that of `Cl_(2)`.
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Account for the following : (i) NH_(3) is a stronger base than PH_(3) (ii) Sulphur has a greater tendency for catenation than oxygen. (iii) Bond dissociation energy of F_(2) is less than that of Cl_(2) .

Assertion: Bond dissociation energy of F_(2) molecule is less than that of Cl_(2) molecule. Reason: Due to inter-electronic repulsion between F atom, F-F bond length in F_(2) molecule is higher than Cl-Cl bond lengthh in Cl_(2) molecule.

Knowledge Check

  • The bond dissociation energy of B-F in BF_(3) is 646 kJ mol^(-1) whereas that of C-F in CF_(4) is 515 kJ mol^(-1) . The correct reason for higher B-F bond dissociation energy as compared to that of C-F in CF_(4) is

    A
    stronger `sigma` bond between B and F in `BF_(3)` as compared to that between C and F in `CF_(4)`
    B
    significant `p pi- p pi` interaction between B and F in `BF_(3)` whereas there is no possibility of such interaction between C and F in `CF_(4)`
    C
    lower degree of `p pi- p pi` interaction between B and F in `BF_(3)` than that between C and F in `CF_(4)`
    D
    smaller size of B - atoms as compared to that of C-atom
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