Home
Class 12
CHEMISTRY
p-Amino-N,N-dimethylaniline is added to ...

p-Amino-N,N-dimethylaniline is added to a strongly acidic solution of X. The resulting solution is treated with a few drops of aqueous solution of Y to yield blue colouration due to the formation of methylene blue. Treatment of aqueous solution of Y with reagent potassium hexacyanoferrate (II) leads to the formation of an intense blue precipitate. The precipitate dissolves on excess addition of the reagent. Similarly, the treatment of the solution of Y with the solution of potassium hexacyanoferrate (III) leads to a brown colouration due to the formation of Z.
Q. Compound X is

A

`NaNO_3`

B

`NaCl`

C

`Na_2SO_4`

D

`Na_2S`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the question, we need to analyze the information provided step by step. ### Step 1: Identify the structure of p-Amino-N,N-dimethylaniline The first step is to understand the structure of p-Amino-N,N-dimethylaniline. It has an amino group (-NH2) and two methyl groups (-CH3) attached to the nitrogen atom, and it is para-substituted on the benzene ring. ### Step 2: Reaction with a strongly acidic solution (Compound X) When p-Amino-N,N-dimethylaniline is added to a strongly acidic solution (let's denote it as X), it is likely protonated, which makes it more reactive. The acidic environment is necessary for the formation of methylene blue. ### Step 3: Formation of Methylene Blue The resulting solution is treated with an aqueous solution of Y, which contains Fe³⁺ ions. The reaction between p-Amino-N,N-dimethylaniline and Fe³⁺ leads to the formation of methylene blue, which is a blue-colored compound. ### Step 4: Treatment of Y with Potassium Hexacyanoferrate (II) Next, we treat the aqueous solution of Y with potassium hexacyanoferrate (II) [K4[Fe(CN)6]]. This leads to the formation of an intense blue precipitate. The precipitate is likely Prussian blue (Fe₃[Fe(CN)₆]₂), which is known to form from the reaction of Fe²⁺ with Fe³⁺ in the presence of cyanide ions. ### Step 5: Treatment of Y with Potassium Hexacyanoferrate (III) When the solution of Y is treated with potassium hexacyanoferrate (III) [K3[Fe(CN)6]], it results in a brown coloration due to the formation of a brown precipitate, which is likely a complex of iron with cyanide ions. ### Step 6: Identify Compound X From the information given, we need to identify what compound X is. The only options provided are sodium salts, and since we are looking for a strongly acidic solution, the most suitable choice is sodium sulfide (Na₂S). Sodium sulfide in solution can release sulfide ions (S²⁻), which can create an acidic environment when reacting with the amine. ### Conclusion Thus, the compound X is **Na₂S**.

To solve the question, we need to analyze the information provided step by step. ### Step 1: Identify the structure of p-Amino-N,N-dimethylaniline The first step is to understand the structure of p-Amino-N,N-dimethylaniline. It has an amino group (-NH2) and two methyl groups (-CH3) attached to the nitrogen atom, and it is para-substituted on the benzene ring. ### Step 2: Reaction with a strongly acidic solution (Compound X) When p-Amino-N,N-dimethylaniline is added to a strongly acidic solution (let's denote it as X), it is likely protonated, which makes it more reactive. The acidic environment is necessary for the formation of methylene blue. ...
Doubtnut Promotions Banner Mobile Dark
|

Topper's Solved these Questions

  • D AND F BLOCK ELEMENTS

    CENGAGE CHEMISTRY ENGLISH|Exercise Archives Multiple Correct|8 Videos
  • D AND F BLOCK ELEMENTS

    CENGAGE CHEMISTRY ENGLISH|Exercise Archives Single Correct|29 Videos
  • D AND F BLOCK ELEMENTS

    CENGAGE CHEMISTRY ENGLISH|Exercise Exercises True False|10 Videos
  • COORDINATION COMPOUNDS

    CENGAGE CHEMISTRY ENGLISH|Exercise Archives Subjective|18 Videos
  • ELECTROCHEMISTRY

    CENGAGE CHEMISTRY ENGLISH|Exercise Archieves Subjective|35 Videos

Similar Questions

Explore conceptually related problems

When NH_4OH is added to copper sulphate solution, blue colour is obtained due to formation of

What will be the effect of the following solutions on blue litmus ? Aqueous solution of sodium carbonate.

When ammonia is added to cupric salt solution, the deep blue colour is observed it is due to the formation of:

What will be the effect of the following solutions on blue litmus ? Aqueous solution of magnesium chloride.

The increase in the solubility of iodine in an aqueous solution of potassium iodide is due to the formation of ___________ .

A solution of sodium in liquid ammonia is blue in colour due to:

Which is not easily precipitated for aqueous solution ?

When excess of dilute NH_(4)OH is added to an aqueous solution of copper sulphate an intense blue colour is developed.This is due to the formation of:

An aqueous solution of CoCl_2 on addition of excess of concentrated HCl turns blue due to formation of

A solution of a metal ion when treated with KI solution gives a red precipitate which dissolves in excess of KI solution to give a colourless solution. Moreover, the solution of the same metal ion on treatment with the solution of cobalt (II) thiocyanate gives rise to a deep blue crystalline precipitate. The metal ion is