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Give reason for the fact that amongst Ni...

Give reason for the fact that amongst `Ni(CO)_(4)[Ni(CN)_(4)]^(2-)` and `NiCI_(4)^(2-), Ni(CO)_(4)` and `[Ni(CN)_(4)]^(2-)` are diamagnetic whereas `[NiCI_(4)]^(2)` is paramagnetic are diamagnetic whereas` [NiCI_(4)]^(2)` is paramagnetic .

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To determine why `Ni(CO)4` and `[Ni(CN)4]^(2-)` are diamagnetic while `[NiCl4]^(2-)` is paramagnetic, we need to analyze the electronic configuration of nickel in these coordination compounds and how the ligands affect the d-orbitals through crystal field splitting. ### Step-by-Step Solution: 1. **Identify the oxidation state of Nickel**: - In all three complexes, nickel is in the +2 oxidation state. The electronic configuration of Ni in its elemental form is `[Ar] 3d^8 4s^2`. When it loses two electrons to form Ni²⁺, the configuration becomes `[Ar] 3d^8`. 2. **Determine the nature of the ligands**: ...
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Amongst Ni(CO)_(4),[Ni(CN)_(4)]^(2-) and NiCl_(4)^(2-) :

Amongst Ni(CO)_(4),[Ni(CN)_(4)]^(2-) and [NiCl_(4)]^(2-)

Knowledge Check

  • Ni(CO)_(4) is

    A
    tetrahedral
    B
    square planar
    C
    linear
    D
    octahedral .
  • Give reason for the statement [Ni(CN)_(4)]^(2-) is diamagnetic while [NiCl_(4)]^(2-) is paramagnetic in nature .

    A
    In `[NiCl_(4)]^(2-)` no unpaired electrons are present while in `[Ni(CN)_(4)]^(2-)` two unpaired electrons are present
    B
    In `[Ni(CN)_(4)]^(2-)` , no unpaired electrons are present while in `[NiCl_(4)]^(2-)` two unpaired electrons are present .
    C
    `[NiCl_(4)]^(2-)` shows `dsp^(2)` hybridisation hence it is paramagnetic .
    D
    `[Ni(CN)_(4)]^(2-)` shows `sp^(3)` hybridisation hence it is diamagnetic .
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    EAN of Ni(CO)_(4)

    Write true or false: [NiCI_(4)]^(2-) is diamagnetic in nature .

    [NiCl_(4)]^(2-) is paramagnetic while [Ni(CO)_(4)] is diamagnetic though both are tetrahedral Why?

    [Cr(NH_3)_6]^(3+) is paramagnetic while [Ni(CN)_4]^(2-) is diamagnetic. Explain why?

    Explain the following giving reasons [NiCI_(4)]^(2-) is tetrahedral and paramagnetic whereas [Ni(CN)_(4)]^(2-) is square plannar and dimagnetic.

    The IUPAC name of [Ni(CN)_(4)]^(2-) is