When `K_(4)[Fe(CN)_(6)]` is treated with `FeCI_(3)` a blue colour is obtained It is due to the formation of .

Options

A. `Fe^(II)[Fe^(III)(CN)_(6)]^(Θ)`
B. `Fe^(III)[Fe^(II)(CN)_(6)]^(Θ)`
C. Both (a) and (b)
D. None of these

Answer

C

Explanation

X -ray studies have established that Prussian blue and Turnbull 's blue are identical `Fe^(3+)` partially oxidises
`[Fe^(II) (CN)_(6)]^(4-)` forming some `[Fe^(III) (CN)_(6)]^(3-)`
Thus `Fe[Fe(CN)_(6)]^(Θ)` is formed .