Turnbull's blue and prussian's blue respectively are `KFe^(II)[Fe^(III)(CN)_(6)]` and ` KFe^(II)(Fe^(11)(CN)_(6)]`. True or False?

Explanation

To determine whether the statement "Turnbull's blue and Prussian's blue respectively are KFe^(II)[Fe^(III)(CN)_(6)] and KFe^(II)(Fe^(II)(CN)_(6)]" is true or false, we need to analyze the chemical compositions of both Turnbull's blue and Prussian blue.

### Step-by-Step Solution:

1. **Identify the Compounds**:
- Turnbull's blue is formed when ferrous ions (Fe²⁺) react with potassium ferricyanide (K₃[Fe(CN)₆]).
- Prussian blue is formed when ferric ions (Fe³⁺) react with potassium ferrocyanide (K₄[Fe(CN)₆]).

2. **Write the Chemical Formulas**:
- The formula for Turnbull's blue is KFe₂[Fe(CN)₆]. This indicates that it contains one ferrous ion (Fe²⁺) and one ferric ion (Fe³⁺).
- The formula for Prussian blue is KFe₃[Fe(CN)₆]. This indicates that it contains three ferrous ions (Fe²⁺) and two ferric ions (Fe³⁺).

3. **Analyze the Given Statement**:
- The statement claims that Turnbull's blue is KFe^(II)[Fe^(III)(CN)₆] and Prussian's blue is KFe^(II)(Fe^(II)(CN)₆].
- However, according to our analysis:
- Turnbull's blue should be KFe₂[Fe(CN)₆], not KFe^(II)(Fe^(II)(CN)₆].
- Prussian blue should be KFe₃[Fe(CN)₆], which is not correctly represented in the statement.

4. **Conclusion**:
- Since the chemical formulas provided in the statement do not accurately reflect the true compositions of Turnbull's blue and Prussian blue, the statement is **False**.

### Final Answer:
**False**