`BaBr_(2)` gives yellow ppt with `AgNO_(3)` as well as with `K_(2)CrO_(4)`. (T\F)

Explanation

To determine whether the statement "BaBr₂ gives yellow ppt with AgNO₃ as well as with K₂CrO₄" is true or false, we can analyze the reactions involved step by step.

### Step 1: Reaction of BaBr₂ with AgNO₃
1. **Write the chemical equation**: When barium bromide (BaBr₂) reacts with silver nitrate (AgNO₃), the following reaction occurs:
\[ \text{BaBr}_2 + 2 \text{AgNO}_3 \rightarrow 2 \text{AgBr} + \text{Ba(NO}_3\text{)}_2 \]
2. **Identify the precipitate**: In this reaction, silver bromide (AgBr) is formed, which is a light yellow precipitate.

### Step 2: Reaction of BaBr₂ with K₂CrO₄
1. **Write the chemical equation**: When barium bromide (BaBr₂) reacts with potassium chromate (K₂CrO₄), the following reaction occurs:
\[ \text{BaBr}_2 + \text{K}_2\text{CrO}_4 \rightarrow \text{BaCrO}_4 + 2 \text{KBr} \]
2. **Identify the precipitate**: In this reaction, barium chromate (BaCrO₄) is formed, which is a yellow precipitate.

### Conclusion
Since BaBr₂ gives a light yellow precipitate with AgNO₃ (AgBr) and a yellow precipitate with K₂CrO₄ (BaCrO₄), we can conclude that the statement is **true**.

### Final Answer
**True**

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