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A mixture when heated with dil H(2)SO(4)...

A mixture when heated with dil `H_(2)SO_(4)` does not evolve brown vapours but when heated with conc `H_(2)SO_(4)`, brown vapours are obtained. with `AgNO_(3)` soin do not give any precipitate .The mixture contain

A

`NO_(2)^(Theta)`

B

`NO_(3)^(Theta)`

C

`I^(Theta)`

D

`Br^(Theta)`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem step by step, we need to analyze the given information about the mixture and the reactions involved. ### Step 1: Analyze the behavior with dilute H₂SO₄ - The mixture does not evolve brown vapors when heated with dilute H₂SO₄. This indicates that the anions present in the mixture do not produce brown gases under these conditions. **Hint:** Consider what types of anions typically do not react with dilute sulfuric acid to produce brown gases. ### Step 2: Analyze the behavior with concentrated H₂SO₄ - When heated with concentrated H₂SO₄, brown vapors are obtained. This suggests that the anion present in the mixture must be capable of producing brown gases (like NO₂) when reacted with concentrated sulfuric acid. **Hint:** Think about which anions can react with concentrated sulfuric acid to produce brown gases. ### Step 3: Consider the reaction with AgNO₃ - The mixture does not give any precipitate with AgNO₃. This is crucial because certain anions (like I⁻ and Br⁻) would form precipitates (AgI and AgBr) when reacted with silver nitrate. **Hint:** Recall which anions typically form precipitates with AgNO₃ and eliminate them from consideration. ### Step 4: Identify the possible anions - Since the mixture does not give a precipitate with AgNO₃, we can eliminate I⁻ and Br⁻ from our list of possible anions. - The only anion that fits the criteria of producing brown vapors when reacted with concentrated H₂SO₄ and not forming a precipitate with AgNO₃ is the nitrate ion (NO₃⁻). **Hint:** Check the reactions of other common anions with concentrated H₂SO₄ to see if they produce brown gases. ### Step 5: Conclusion - Based on the analysis, the anion present in the mixture is nitrate (NO₃⁻). **Final Answer:** The mixture contains the nitrate ion (NO₃⁻).
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    C
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    D
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