A metal chloride on heating with `K_(2)Cr_(2)O_(7)` gives a yellow ppt insoluble in acetic acid .The metal may be

Options

A. Hg
B. Zn
C. Pb
D. Ag

Answer

To solve the question, we need to identify a metal chloride that, when heated with potassium dichromate (K₂Cr₂O₇), produces a yellow precipitate that is insoluble in acetic acid. Here’s the step-by-step solution:

### Step 1: Understand the Reaction
When a metal chloride is heated with potassium dichromate, a reaction occurs that can lead to the formation of a precipitate. The key is to identify which metal chloride produces a yellow precipitate.

### Step 2: Identify the Yellow Precipitate
The yellow precipitate formed in this reaction is lead dichromate (PbCr₂O₇). This compound is known for its distinct yellow color.

### Step 3: Write the Reaction
The chemical reaction can be represented as follows:
\[ \text{Metal Chloride} + K_2Cr_2O_7 \rightarrow PbCr_2O_7 (s) + 2 KCl \]
Here, the metal chloride in question is lead chloride (PbCl₂).

### Step 4: Check Solubility in Acetic Acid
It is important to note that lead dichromate (PbCr₂O₇) is insoluble in acetic acid (CH₃COOH). This aligns with the conditions given in the question.

### Step 5: Conclusion
Based on the above steps, we conclude that the metal chloride that meets the criteria is lead chloride (PbCl₂).

### Final Answer
The metal chloride is **Lead Chloride (PbCl₂)**.

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