2-Methyl butane reacting with `Br_(2)` in sunlight mainly gives:

Options

A. (a) 1-Bromo-2-methyl butane
B. (b) 2-Bromo-2-methyl butane
C. (c) 2-Bromo-3-methyl butane
D. (d) 1-Bromo-3-methyl butane

Explanation

To determine the main product of the reaction between 2-methylbutane and bromine (Br₂) in the presence of sunlight, we can follow these steps:

### Step-by-Step Solution:

1. **Identify the Structure of 2-Methylbutane**:
- 2-Methylbutane has the following structure:
```
CH3
|
CH3-CH-CH2-CH3
|
CH2
```
- It consists of a butane chain with a methyl group on the second carbon.

2. **Understand the Reaction Conditions**:
- The reaction occurs in the presence of sunlight, which initiates a free radical bromination process. This means that Br₂ will dissociate into bromine radicals (Br•) under UV light.

3. **Initiation Step**:
- The initiation step involves the homolytic cleavage of the Br-Br bond:
```
Br2 → 2 Br•
```
- This generates two bromine radicals.

4. **Propagation Steps**:
- The bromine radical will react with the 2-methylbutane. The most stable radical that can form will dictate the main product. The possible carbon radicals that can form are:
- Primary (1°) at the end carbons
- Secondary (2°) at the second carbon
- Tertiary (3°) at the carbon with the methyl group.

- The bromine radical will preferentially attack the tertiary carbon (C-2) because it forms a more stable tertiary radical:
```
CH3-CH(Br)-CH2-CH3 (2-bromo-2-methylbutane)
```

5. **Formation of the Product**:
- The reaction of the bromine radical with the tertiary carbon leads to the formation of 2-bromo-2-methylbutane:
```
CH3-CH(Br)-CH2-CH3 + HBr
```

6. **Termination Step**:
- The termination step involves the combination of radicals to form stable products. However, the main product remains 2-bromo-2-methylbutane.

### Final Answer:
The main product formed when 2-methylbutane reacts with Br₂ in sunlight is **2-bromo-2-methylbutane**.

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